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melamori03 [73]
3 years ago
15

Clara has 9 pounds of apples. She needs 1 1/4 pounds to make one apple pie. If she saves 2 pounds for applesauce, how many pies

can she make?
Mathematics
2 answers:
sattari [20]3 years ago
8 0

Answer:

She can make 6 pies.

Ierofanga [76]3 years ago
7 0

Answer:

She can make 6 pies.

Step-by-step explanation:

Subtract 9-1.5=7.5

then 7.5/1.25= 6.04

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I think it's y=3x+5.


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3 0
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A) –9 + 3 = ?<br>b) -7 + ? = -9​
ipn [44]
A= -6
B= -7+16=9
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During his vacation, Dalyn rents a small boat from a rental service that charges a flat fee of $30 plus $10 per hour (including
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As a bowl of soup cools, the temperature of the soup is given by the twice-differentiable function H for 0<img src="https://tex.
Aleks04 [339]

The rate of change of temperature with time at a point in time is given by

the derivative of the function for the temperature of the soup.

The correct responses are;

  • a) H'(5) is approximately<u> -2.6 degrees Celsius per minute</u>.
  • b) Yes
  • c) The equation for the line tangent is<u> y = -3.6·t + 90.8</u>
  • The approximate value of C(5) is <u>72.8 °C</u>

  • d) The rate of change of the temperature of the soup at t = 3 minutes is <u>-3.6 degrees Celsius per minute</u>.

Reasons:

a) From the data in the table, we have;

The approximate value of H'(5) is given by the average value of the rate of

change of the temperature with time between points, t = 3, and t = 8

Therefore;

\displaystyle H'(5) = \mathbf{\frac{H(8) - H(3)}{8 - 3}}

Which gives;

\displaystyle H'(5) =  \frac{80 - 67}{8 - 3} = \mathbf{2.6}

Therefore, H'(5) = <u>-2.6°C per minute</u>

b) Given that the function is twice differentiable over the interval, 0 ≤ t ≤ 12, the function for the change in temperature is continuous in the interval 0 ≤ t ≤ 12

At t = 0, H(0) = 90 °C

At t = 12, H(12) = 58 °C

  • 58 °C < 60 < 90 °C

Therefore, there exist a temperature, of 60 °C between 90° C and 58 °C

c) The given derivative of <em>C</em> is, C'(t) = \mathbf{-3.6 \cdot e^{-0.05 \cdot t}}

At t = 3, we have;

The \ slope \ at \ t = 3 \ is \ C'(3) = -3.6 \cdot e^{-0.05 \times 3} \approx -3.1

Therefore, we have;

y - 80 ≈ -3.1 × (x - 3)

The equation for the tangent is; y = -3.6 × (x - 3) + 80

y = -3.6·x + 10.8 + 80 = -3.6·x + 90.8

  • The equation for the tangent is; <u>y = -3.6·x + 90.8</u>

The  value of C(5) is approximately, C(5) ≈ -3.6 × 5 + 90.8 = 72.8

  • <u>C(5) ≈ 72.8°</u>

<u />

d) Based on the the model above, the rate at which the temperature of the

soup is changing at t = 3 minutes is <u>-3.6 degrees per minute</u>.

Learn more about calculus and concepts here:

brainly.com/question/20336420

8 0
3 years ago
Help please, also provide work
Andreas93 [3]

Answer:

9) 128
10) 78
11) 31
12) 148

Step-by-step explanation:


9) we know that the segment across from the angle 48° is double the angle.

48 · 2 = 96

The segments around the circle should all add up to 360 so we add the two segments we know to find the unknown segment.

136 + 96 = 232

360 - 232 = 128

The answer for 9 is 128.

10)

61 + 80 = 141

180 - 141 = 39

39 * 2 = 78

The answer for question 10 is 78.

11)

236 + 62 = 298

360 - 298 = 62

62 ÷ 2 = 31

The answer for question 11 is 31.

12)

50 · 2 = 100

100 + 112 = 212

360 - 212 = 148

The answer for question 12 is 148.

8 0
2 years ago
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