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3 years ago

I’m not sure how to solve this. Please show how you solve this problem, thank you.

Mathematics

1 answer:

7nadin3 [17]3 years ago

6 0

Answer:

Pretend that H is the midpoint of AB, connect O and H

=> OH is the median of ΔOAB

Since we know that OA = OB => ΔOAB is an isosceles triangle

=> OH is also the height of ΔOAB

=> ∠OBA = ∠OAB = (180° - ∠AOB)/2 = (180° - 120°)/2 = 60°/2 = 30°

Now look at ΔOHB (that you create by connecting O and H)

We have:

cos30° = BH/OB

=> BH = cos30° · OB = √3/2 · x = (√3 x)/2

Because we have H as the midpoint of AB, we know that:

AB = 2 · BH = 2 · (√3 x)/2 = √3 x

So the answer is B

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Answer:

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Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

We are given that Population Mean, $\mu$ = 2.58 and Standard deviation, $\sigma$ = 0.75

Also, a random sample (n) of 110 households is taken.

Let Xbar = sample mean household size

The z score probability distribution for sample mean is give by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

So, probability that the sample mean household size is between 2.50 and 2.66 people = P(2.50 < Xbar < 2.66)

P(2.50 < Xbar < 2.66) = P(Xbar < 2.66) - P(Xbar $\leq$ 2.50)

P(Xbar < 2.66) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{2.66-2.78}{\frac{0.75}{\sqrt{110} } }$ ) = P(Z < -1.68) = 1 - P(Z 1.68)

= 1 - 0.95352 = 0.04648

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= 1 - 0.99996 = 0.00004

Therefore, P(2.50 < Xbar < 2.66) = 0.04648 - 0.00004 = 0.046

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