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2 years ago

Pls help ILL GIVE BRAINLIST

Mathematics

2 answers:

Tems11 [23]2 years ago

7 0

Answer:J

Step-by-step explanation:

27/3=9-3=6

27/9=3+3=6

6=6

Jobisdone [24]2 years ago

5 0

Answer:

Step-by-step explanation:

maybe I hope it helps :)

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Find the perimeter and area of the figure.

Travka [436]

Answer:

The perimeter is 20 cm.

The area is 25 cm^2.

Step-by-step explanation:

The perimeter is the distance around the figure.

This is a square, so each side is the same length.

There are four sides, so

5 + 5 + 5 + 5 = 20 cm

The area of the figure is

s^2

where s is a side

so 5 * 5 = 25 cm^2

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2 years ago

More of my brothers wwork for yalll have fun and tysm!

IceJOKER [234]

Answer: 3/4 x 48
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2 years ago

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The population of a species of rabbit triples every year. This can be modeled by f(x) = 4(3)x and f(5) = 972. What does the 972

Alona [7]

972 represent the total population of the rabbits after five yours.
Answer: B

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3 years ago

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Find x: explain if you can!

Sergio039 [100]

Answer:

x is 97

Step-by-step explanation:

the interior angles have to equal 180 and the exterior angles have to come to 360 degrees

so you already know 23 to find the one by the 106 degree you use the linear pair postulate ( angles on a straight line will equal 180) so 180-106 equals 74. Now you have 2 of the three interior angles. To find the third you take 180 - 74 - 23 which equals 83 then you can use the linear pair postulate again and take 180-83 to get your answer for x which equals 97

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3 years ago

(x^2y+e^x)dx-x^2dy=0

klio [65]

It looks like the differential equation is

$\left(x^2y + e^x\right) \,\mathrm dx - x^2\,\mathrm dy = 0$

Check for exactness:

$\dfrac{\partial\left(x^2y+e^x\right)}{\partial y} = x^2 \\\\ \dfrac{\partial\left(-x^2\right)}{\partial x} = -2x$

As is, the DE is not exact, so let's try to find an integrating factor µ(x, y) such that

$\mu\left(x^2y + e^x\right) \,\mathrm dx - \mu x^2\,\mathrm dy = 0$

*is* exact. If this modified DE is exact, then

$\dfrac{\partial\left(\mu\left(x^2y+e^x\right)\right)}{\partial y} = \dfrac{\partial\left(-\mu x^2\right)}{\partial x}$

We have

$\dfrac{\partial\left(\mu\left(x^2y+e^x\right)\right)}{\partial y} = \left(x^2y+e^x\right)\dfrac{\partial\mu}{\partial y} + x^2\mu \\\\ \dfrac{\partial\left(-\mu x^2\right)}{\partial x} = -x^2\dfrac{\partial\mu}{\partial x} - 2x\mu \\\\ \implies \left(x^2y+e^x\right)\dfrac{\partial\mu}{\partial y} + x^2\mu = -x^2\dfrac{\partial\mu}{\partial x} - 2x\mu$

Notice that if we let µ(x, y) = µ(x) be independent of y, then ∂µ/∂y = 0 and we can solve for µ :

$x^2\mu = -x^2\dfrac{\mathrm d\mu}{\mathrm dx} - 2x\mu \\\\ (x^2+2x)\mu = -x^2\dfrac{\mathrm d\mu}{\mathrm dx} \\\\ \dfrac{\mathrm d\mu}{\mu} = -\dfrac{x^2+2x}{x^2}\,\mathrm dx \\\\ \dfrac{\mathrm d\mu}{\mu} = \left(-1-\dfrac2x\right)\,\mathrm dx \\\\ \implies \ln|\mu| = -x - 2\ln|x| \\\\ \implies \mu = e^{-x-2\ln|x|} = \dfrac{e^{-x}}{x^2}$