Solve the inequality.−8≤2/5(k−2) The / is not a division sign.

Susan purchased n notebooks. They were 4 dollars each. Write an equation to represent the total cost c that Susan paid

Monica [59]

N4=c

n times 4, n being a number of notebooks, would equal c, or the overall cost.

4 0

3 years ago

HEY CAN ANYONE HELP ME!

nataly862011 [7]

Answer:

Given: In triangle ABC and triangle DBE where DE is parallel to AC.

In ΔABC and ΔDBE

$DE || AC$ [Given]

As we know, a line that cuts across two or more parallel lines. In the given figure, the line AB is a transversal.

Line segment AB is transversal that intersects two parallel lines. [Conclusion from statement 1.]

Corresponding angles theorem: two parallel lines are cut by a transversal, then the corresponding angles are congruent.

then;

$\angle BDE \cong \angle BAC$ and

$\angle BEC \cong \angle BCA$

Reflexive property of equality states that if angles in geometric figures can be congruent to themselves.

by Reflexive property of equality:

$\angle B \cong \angle B$

By AAA (Angle Angle Angle) similarity postulates states that all three pairs of corresponding angles are the same then, the triangles are similar

therefore, by AAA similarity postulates theorem

$\triangle ABC \sim \triangle DBE$

Similar triangles are triangles with equal corresponding angles and proportionate side.

then, we have;

$\frac{BD}{BA}$ [By definition of similar triangles]

therefore, the missing statement and the reasons are

Statement Reason

3. $\angle BDE \cong \angle BAC$ Corresponding angles theorem

and $\angle BEC \cong \angle BCA$

5. $\triangle ABC \sim \triangle DBE$ AAA similarity postulates

6. BD over BA Definition of similar triangle

7 0

3 years ago

Read 2 more answers

What is the surface area of a cylinder that is 5 centimeters high and has a diameter of 1.5 centimeters?

labwork [276]

Answer:

D is the answer.

6 0

3 years ago

This is a geometry question, i need something quickly :)

Marysya12 [62]

Answer:

hope it helps mark me brainlieast!

Step-by-step explanation:

For triangle ABC with sides a,b,c labeled in the usual way,

c2=a2+b2−2abcosC

We can easily solve for angle C .

2abcosC=a2+b2−c2

cosC=a2+b2−c22ab

C=arccosa2+b2−c22ab

That’s the formula for getting the angle of a triangle from its sides.

The Law of Cosines has no exceptions and ambiguities, unlike many other trig formulas. Each possible value for a cosine maps uniquely to a triangle angle, and vice versa, a true bijection between cosines and triangle angles. Increasing cosines corresponds to smaller angles.

−1≤cosC≤1

0∘≤C≤180∘

We needed to include the degenerate triangle angles, 0∘ and 180∘, among the triangle angles to capture the full range of the cosine. Degenerate triangles aren’t triangles, but they do correspond to a valid configuration of three points, namely three collinear points.

The Law of Cosines, together with sin2θ+cos2θ=1 , is all we need to derive most of trigonometry. C=90∘ gives the Pythagorean Theorem; C=0 and C=180∘ give the foundational but often unnamed Segment Addition Theorem, and the Law of Sines is in there as well, which I’ll leave for you to find, just a few steps from cosC= … above. (Hint: the Law of Cosines applies to all three angles in a triangle.)

The Triangle Angle Sum Theorem, A+B+C=180∘ , is a bit hard to tease out. Substituting the Law of Sines into the Law of Cosines we get the very cool

2sinAsinBcosC=sin2A+sin2B−sin2C

Showing that’s the same as A+B+C=180∘ is a challenge I’ll leave for you.

In Rational Trigonometry instead of angle we use spreads, squared sines, and the squared form of the formula we just found is the Triple Spread Formula,

4sin2Asin2B(1−sin2C)=(sin2A+sin2B−sin2C)2

true precisely when ±A±B±C=180∘k , integer k, for some k and combination of signs.

This is written in RT in an inverted notation, for triangle abc with vertices little a,b,c which we conflate with spreads a,b,c,

(a+b−c)2=4ab(1−c)

Very tidy. It’s an often challenging third degree equation to find the spreads corresponding to angles that add to 180∘ or zero, but it’s a whole lot cleaner than the trip through the transcendental tunnel and back, which almost inevitably forces approximation.

6 0

3 years ago

Will the probabilities from an experiment with 20 trials be exactly the same if you repeat the experiment? (Explain your thinkin

trasher [3.6K]

Hello, each and every one of your 20 trials should be very similar to the one prior, as long as you keep the data the same, such as how much water you use, or the length of an object, etc.

I hope that helped, if it did in any way, place mark as brainliest, thank, and rate me! If you need any more help or have any more questions, please feel free to ask!

You can follow me on IG: kaitlyn.kannasoot

4 0

3 years ago