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anyanavicka [17]
3 years ago
8

PLEASE HELP ME (it’s numbers 2-5) thanks! ☺️

Mathematics
1 answer:
Alisiya [41]3 years ago
3 0
I’m stuck on the sameee
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For tall heterozygotes with antennae, the offspring are:
Misha Larkins [42]

Recombinant frequency between T and A is 12%

<u>Explanation:</u>

<u></u>

Two characters are considered - height and antennae

Traits of height - Tall and Dwarf

Traits of antennae - Antennae and No antennae

<u>Given:</u>

<u />

Tall-antennae (46) and dwarf-no antennae (42) are the wild type.

Dwarf- antennae (7) and tall- no antennae (5) are the recombinants.

Total possibilities = 100

Recombinant frequency = \frac{7}{100} + \frac{5}{100}

Recombinant frequency = \frac{12}{100}

Recombinant frequency in percentage = \frac{12}{100} X 100 = 12%

Therefore, recombinant frequency between T and A is 12%

8 0
3 years ago
In which step does a mistake first occur?
kumpel [21]

Answer:

Step 3. 4 ÷ 2

Step 4. 2

these two steps are wrong

(24 ÷ 3 + 10) - 14 ÷ 2

(8 + 10) - 14 ÷ 2

(8 + 10) - 7

18 - 7

11

Note : See the explanation and get the answer

7 0
3 years ago
Read 2 more answers
A deposit of $4,500 at 5% for 3 years:
tekilochka [14]
I = 4500 × 0.05 × 3
<span>I = $ 675.00</span>
7 0
3 years ago
James practiced Piano for 48 Minutes. Alisa practiced 5 times long as James. How many Minutes did Alisa Practice? how many minut
ANEK [815]

Answer:

Alisa practiced for 240 minutes (4 hours). In total, they practiced for 288 minutes (4.8 hours).

Step-by-step explanation:

If James practiced for 48, and Alisa practiced 5 times as long, then we would multiply 48 by 5 (240 minutes).

If we want to find how many minutes in total they practiced, then we would add 240 minutes (Alisa's practice time) and 48 minutes (James' practice time) together, which would equal 288 minutes (4.8 hours).

Equation: y=48+x

3 0
3 years ago
Please I need help
Citrus2011 [14]

Answer:

x: C

y: A

z:

Step-by-step explanation:

In a 45-45-90 triangle, the hypotenuse is larger than either of the legs by a factor of \sqrt{2}. The length of x is therefore:

12\cdot \sqrt{2}=12\sqrt{2}

In a 30-60-90 triangle, the longer leg is larger than the shorter leg by a factor of \sqrt{3}. Therefore:

y=\dfrac{12}{\sqrt{3}}=\dfrac{12\sqrt{3}}{3}=4\sqrt{3}

The hypotenuse of the 30-60-90 triangle is twice larger than the smallest leg, so it has a length of 8\sqrt{3}.

By the pythagorean theorem, you can find z+y:

z+y=\sqrt{(12\sqrt{2})^2-12^2}=\sqrt{288-144}=12\\\\4\sqrt{3}+z=12 \\\\z=12-4\sqrt{3}

Hope this helps!

4 0
3 years ago
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