Answer:
M v^2 / R = centripetal force
For Red: M v^2 / R = 5 * 9^2 / 1.5 = 270
For Blue M v^2 / R = 270 = 25 * 1.8^2 / Rb
So Rb = 25 * 1.8^2 / 270 = .3 m
Answer: All of the above.
Explanation:
Answer:
Living cells can give birth to children and non living cells can't be reproduced.
Explanation:
Answer:
a. Light pollution refers to light used for human activities that brightens the sky and hinders astronomical observations.
Explanation:
Light pollution is due to the excessive and misdirected use of artificial light. Light bulbs are often design in an incorrect way, since a great part of its light is not completely directed to the ground and an important percentage is emitted to the sky in where will be scattered and reflected back to ground by the particles in the atmosphere. That brings as an effect a sky glow, therefore the visibility of astronomical objects will be extremely reduce.
Hence, professional astronomical research and amateur observations will be affected. Light pollution has a negative impact on bird migration at night and in the health of difference species, humans also.
Answer:
![F= 6.69*10^{-10}N](https://tex.z-dn.net/?f=F%3D%206.69%2A10%5E%7B-10%7DN)
Explanation:
To find the force we proceed by defining the variables we have,
![m= 160g\\n= 4.40*10^8\\h=115m\\B=0.2T\\e= 1.602*10^{-19}c](https://tex.z-dn.net/?f=m%3D%20160g%5C%5Cn%3D%204.40%2A10%5E8%5C%5Ch%3D115m%5C%5CB%3D0.2T%5C%5Ce%3D%201.602%2A10%5E%7B-19%7Dc)
The charge on one of the balls is defined under the equation,
![q=ne](https://tex.z-dn.net/?f=q%3Dne)
![q= 4.40*10^8(1.602*10^{-19}c)](https://tex.z-dn.net/?f=q%3D%204.40%2A10%5E8%281.602%2A10%5E%7B-19%7Dc%29)
![q= 7.0488*10^{-11}](https://tex.z-dn.net/?f=q%3D%207.0488%2A10%5E%7B-11%7D)
Due to the height we need to calculate the potential energy at the height of 115m,
![PE=mgh](https://tex.z-dn.net/?f=PE%3Dmgh)
The kinetic energy would be given by
![KE= \frac{1}{2}mv^2](https://tex.z-dn.net/?f=KE%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
From the law of conservation we equate the two equations
![\frac{1}{2}mv^2=mgh](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dmv%5E2%3Dmgh)
![v=\sqrt{2gh}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B2gh%7D)
![v=\sqrt{2(9.8)(115)}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B2%289.8%29%28115%29%7D)
![v= 47.47m/s](https://tex.z-dn.net/?f=v%3D%2047.47m%2Fs)
In this way we now calculate the strength of the particle
![F=qVB](https://tex.z-dn.net/?f=F%3DqVB)
![F= (7.0488*10^{-11})(47.47)(0.2)](https://tex.z-dn.net/?f=F%3D%20%287.0488%2A10%5E%7B-11%7D%29%2847.47%29%280.2%29)
![F= 6.69*10^{-10}N](https://tex.z-dn.net/?f=F%3D%206.69%2A10%5E%7B-10%7DN)