A robot starts from a certain point and moves east for a distance of 5.0 meters, then goes north for 3.0 meters, and then turns
1 answer:
Explanation:
It is given that, a robot starts from a certain point and moves east for a distance of 5.0 meters, then goes north for 3.0 meters, and then turns west for 2.0 meters.
Let east is +x, west is -x north is +y.
When it moves east for a distance of 5.0 meters, it means (5,0)
When it goes north for 3.0 meters, and then turns west for 2.0 meters, it means (0,3) +(-2,0)
(a) x-y coordinates for the resultant vector is (3,3)
(b) The magnitude of the resultant vector for the robot is given by :
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Answer:
Explanation:
The speed of the rocket is given the Tsiolkovsky's differential equation, whose solution is:
Where:
- Initial speed of the rocket, in m/s.
- Exhaust gas speed, in m/s.
- Initial total mass of the rocket, in kg.
- Current total mass of the rocket, in kg.
Let assume that fuel is burned linearly. So that,
The initial total mass of the rocket is:
The fuel consumption rate is:
The function for the current total mass of the rocket is:
The speed function of the rocket is:
The speed of the rocket at given instants are: