A robot starts from a certain point and moves east for a distance of 5.0 meters, then goes north for 3.0 meters, and then turns
1 answer:
Explanation:
It is given that, a robot starts from a certain point and moves east for a distance of 5.0 meters, then goes north for 3.0 meters, and then turns west for 2.0 meters.
Let east is +x, west is -x north is +y.
When it moves east for a distance of 5.0 meters, it means (5,0)
When it goes north for 3.0 meters, and then turns west for 2.0 meters, it means (0,3) +(-2,0)
(a) x-y coordinates for the resultant vector is (3,3)
(b) The magnitude of the resultant vector for the robot is given by :
You might be interested in
Answer:
108.37°C
Explanation:
P₁ = Initial pressure = 101 kPa
V₁ = Initial volume = 530 m³
T₁ = Initial temperature = 10°C = 10+273.15 =283.15 K
P₂ = Final pressure = 101 kPa (because it is open to atmosphere)
V₂ = Final volume = 530 m³
P₁V₁ = n₁RT₁
⇒101×530 = n₁RT₁
⇒53530 J = n₁RT₁
P₂V₂ = n₂RT₂
⇒53530 J = n₂RT₂
Dividing the first two equations we get
∴Temperature must the air in the balloon be warmed before the balloon will lift off is 381.25-273.15 = 108.37°C
Answer:
No. of 100 W bulbs, n = 28,539 bulbs
Given:
Power of a single bulb = 100 W
Time period, T = 1 yr = = 31,536,000 s
mass of matter, m = 1 g =
Solution:
According to Eintein's mass-energy equivalence:
E =
E =
E =
Power of a single bulb, P =
P =
P = 28,53,881 W
No. of 100 W bulbs, n =
n =
n = 28,539