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TiliK225 [7]
3 years ago
6

Which of the following physical properties would tell you about an element's mass per unit volume ratio?

Physics
1 answer:
Igoryamba3 years ago
6 0
Well I can't see the following physical properties you talked about in the question.

Mass per unit volume ratio is called density.
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A flea jumps straight up to a maximum height of 0.540 m . what is its initial velocity v0 as it leaves the ground?
jok3333 [9.3K]
For an uniformly accelerated motion, we can write
2ah=v_f^2-v_0^2
where a=g=-9.81 m/s^2 is the acceleration of this motion, which in this problem is the gravitational acceleration, with a negative sign because it points downward, against the direction of the motion; h=0.540 m is the distance covered by the flea, and v_0 is the initial velocity. 

At the maximum height, the velocity is zero, so v_f =0. Therefore we  can solve to find v_0:
v_0 =  \sqrt{2ah}= \sqrt{2(9.81 m/s^2)(0.540 m)}  =3.25 m/s
3 0
2 years ago
PLEASE HELP TIMED
Igoryamba

Radio waves have longer wavelengths and lower frequencies than microwaves.

infrared is longer wavelengths and lower frequencies than UV light

5 0
3 years ago
Read 2 more answers
Examples of reaction force and action force hewlp​
mrs_skeptik [129]

Answer:

Action-Reaction Force Examples in Everyday Life

Recoil of a Gun.

Swimming.

Pushing the Wall.

Diving off a Raft.

Space Shuttle.

Explanation:

hope this helps

6 0
3 years ago
Read 2 more answers
The magnitude of the Poynting vector of a planar electromagnetic wave has an average value of 0.724 W/m2. What is the maximum va
Hitman42 [59]

Answer:

7.78x10^-8T

Explanation:

The Pointing Vector S is

S = (1/μ0) E × B

at any instant, where S, E, and B are vectors. Since E and B are always perpendicular in an EM wave,

S = (1/μ0) E B

where S, E and B are magnitudes. The average value of the Pointing Vector is

<S> = [1/(2 μ0)] E0 B0

where E0 and B0 are amplitudes. (This can be derived by finding the rms value of a sinusoidal wave over an integer number of wavelengths.)

Also at any instant,

E = c B

where E and B are magnitudes, so it must also be true at the instant of peak values

E0 = c B0

Substituting for E0,

<S> = [1/(2 μ0)] (c B0) B0 = [c/(2 μ0)] (B0)²

Solve for B0.

Bo = √ (0.724x2x4πx10^-7/ 3 x10^8)

= 7.79 x10 ^-8 T

5 0
2 years ago
An ideal air-filled parallel-plate capacitor has round plates and carries a fixed amount of equal but opposite charge on its pla
dusya [7]

Answer:

C). U_f = \frac{U_0}{2}

Explanation:

As we know that capacitance of a given capacitor is

C = \frac{\epsilon_0 A}{d}

now we know that energy stored in the capacitor plates

U_0 = \frac{Q^2}{2C}

here if all the dimensions of the capacitor plate is doubled

then in that case

C' = \frac{\epsilon_0 (4A)}{2d}

here area becomes 4 times on doubling the radius and the distance between the plates also doubles

So new capacitance is now

C' = 2C

so capacitance is doubled

now the final energy stored between the plates of capacitor is given as

U_f = \frac{Q^2}{2C'}

so the final energy is

U_f = \frac{Q^2}{4C}

U_f = \frac{U_0}{2}

4 0
3 years ago
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