Question

In the reaction H2SO4 + 2 NaOH -> Na2SO4 + 2H2O, an equivalence point occurs when 26.34 mL of 0.2321 M NaOH is added to a 36.43 mL portion of H2SO4. What is the [H2SO4]?

Answer 1

The application of acid-base chemistry is used to formulate an answer for your question.
            moles NaOH = c · V = 0.2321 mmol/mL · 26.34 mL = 6.113514 mmol
            moles H2SO4 = 6.113514 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 3.056757 mmol
Hence
            [H2SO4]= n/V = 3.056757 mmol / 36.43 mL = 0.08391 M
The answer to this question is  [H2SO4] = 0.08391 M