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Paladinen [302]
3 years ago
15

Which of the following has the shortest half life?

Chemistry
1 answer:
saul85 [17]3 years ago
8 0
The half-life of carbon 14 is 5,730 years<span>.
</span>The half-life of uranium-238 is about 4.5 billion years
<span>the half-life of uranium-235 </span>about 700 million years<span>, 
</span>the half-life of carbon 14 is 5,730 years<span>.</span>
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If the value of kc at 25oc is 3.7108, and the equilibrium concentrations for n2 and h2 are 0.000105 m and 0.0000542 m, respectiv
frez [133]

Equation of decomposition of ammonia:

N2+3H2->2NH3

Euilibrium constant:

Kc=(NH3)^2/((N2)((H2)^3))

As concentration of N2=0.000105, H2=0.0000542

so equation will become:

3.7=(NH3)^2/(0.000105)*(0.0000542)^3

NH3=√(3.7*0.000105*(0.0000542)^3)

NH3=7.8×10⁻⁹

So concentration of ammonia will be 7.8×10⁻⁹.

5 0
3 years ago
Anybody know this ?? If so help ASAP .
Marizza181 [45]

Answer:

Mechanical Energy

Explanation:

Definition: Mechanical Energy The mechanical energy is

the sum of the kinetic and potential energies.

4 0
3 years ago
Each enzyme has an optimal temperature and pH that it works best in. If enzyme ABC works best at pH 7, but ABC is in a cell with
xeze [42]

Answer:

Less reactions because it does not have the best pH to for that particular enzyme to work in. If it was at pH of 7, ABC would work best and catalyze a lot of reactions, but since the pH is 9 it will not work as efficiently or better so it will catalyze less reactions.

Explanation:

3 0
3 years ago
What is the boiling point in c of a 0.743 m aqueous solution of KCI?
Maksim231197 [3]

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4 0
2 years ago
2. A sample of a gas is occupying a 1500 mL container at a pressure of 3.4 atm and a temperature of 25
lora16 [44]

2. The new pressure, given the data is 3.0 atm

3. The new temperature in K is 361 K

4. The new temperature in K is 348 K

<h3>2. How to determine the new pressure</h3>
  • Initial volume (V₁) = 1500 mL
  • Initial pressure (P₁) = 3.4 atm
  • Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K
  • New temperature (T₂) = 75 °C = 75 + 273 = 348 K
  • New Volume (V₂) = 2000 mL
  • New pressure (P₂) = ?

The new pressure of the gas can be obtained by using the combined gas equation as illustrated below:

P₁V₁ / T₁ = P₂V₂ / T₂

(3.4 × 1500) / 298 = (P₂ × 2000) / 348

Cross multiply

P₂ × 2000 × 298 = 3.4 × 1500 × 348

Divide both sides by 2000 × 298

P₂ = (3.4 × 1500 × 348) / (2000 × 298)

P₂ = 3.0 atm

<h3>3. How to determine the new temperature</h3>
  • Initial volume (V₁) = 450 mL
  • Initial pressure (P₁) = 167 KPa
  • Initial temperature (T₁) = 295 K
  • New pressure (P₂) = 230 KPa
  • New Volume (V₂) = 400 mL
  • New temperature (T₂) =?

The new temperature of the gas can be obtained by using the combined gas equation as illustrated below:

P₁V₁ / T₁ = P₂V₂ / T₂

(167 × 450) / 295 = (230 × 400) / T₂

Cross multiply

T₂ × 167 × 450 = 295 × 230 × 400

Divide both sides by 167 × 450

T₂ = (295 × 230 × 400) / (167 × 450)

T₂ = 361 K

<h3>4. How to determine the new temperature</h3>
  • Initial volume (V₁) = 3.6 L
  • Initial pressure (P₁) = 9.2 atm
  • Initial temperature (T₁) = 298 K
  • New Volume (V₂) = 5.3 L
  • New pressure (P₂) = 7.3 atm
  • New temperature (T₂) =?

The new temperature of the gas can be obtained by using the combined gas equation as illustrated below:

P₁V₁ / T₁ = P₂V₂ / T₂

(9.2 × 3.6) / 298 = (7.3 × 5.3) / T₂

Cross multiply

T₂ × 9.2 × 3.6 = 298 × 7.3 × 5.3

Divide both sides by 9.2 × 3.6

T₂ = (298 × 7.3 × 5.3) / (9.2 × 3.6)

T₂ = 348 K

Learn more about gas laws:

brainly.com/question/6844441

#SPJ1

7 0
2 years ago
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