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3 years ago

1- Which of the following has one double covalent bond?

Chemistry

1 answer:

Zielflug [23.3K]3 years ago

4 0

Answer:

C2H6

Explanation:

Carbon forms bonds with itself, this property is called catenation and Carbon also has a tendency to form multiple bonds, double or triple. ... For C2H6, carbon forms double bond with the other carbon, and each carbon has three hydrogen atoms attached to it.

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When 10.0 grams of sulfur reacts with fluorine gas at a pressure of 2.69 atmosphere in a 5.00 L container at 0.00 degrees Celsiu

Gwar [14]

Answer:

74.1%

Explanation:

Based on the reaction:

S₈ + 16F₂ → 8SF₄

1 mole of sulfur reacts with 16 moles of F₂ to produce 8 moles of SF₄

To solve this question we must find the moles of each reactant in order to find the moles of SF₄. Thus, we can find the theoretical mass produced. Percent yield is:

Percent yield = Actual yield (25.0g) / Theoretical yield * 100

Moles S₈: 256.52g/mol

10.0g * (1mol / 256.52g) = 0.0390 moles

Moles F₂:

PV = nRT

PV/RT = n

Where P is pressure in atm, V is volume in liters, R is gas constant and T is absolute temperature (0°C = 273.15K)

2.69atm*5.00L / 0.082atmL/molK*273.15K = n

0.600 moles = n

For a complete reaction of 0.600 moles F₂ are required:

0.600mol F₂ * (1mol S₈ / 8 mol F₂) = 0.075 moles S₈

As there are just 0.0390 moles, S₈ is limiting reactant.

The theoretical moles and mass of SF₄ -Molar mass: 108.07g/mol- is:

0.0390 moles S₈ * (8mol SF₄ / 1mol S₈) = 0.312 moles SF₄ * (108.07g) =

33.7g

Percent yield = 25.0g / 33.7g * 100

= 74.1%

6 0

3 years ago

A compound consisting of b, n, and h undergoes elemental analysis. the % composition by mass is found to be 40.28% b, 52.20% n,

svp [43]

To compute for the empirical formula, assume there is 100 grams of the compound. That means there is 40.28 g B, 52.2 g N and 7.53 g H. Convert the mass into moles using their molar masses:

40.28 g B * 1 mol/10.811 g = 3.725835 mol B
52.2 g N * 1 mol/14 g = 3.72857 mol N
7.53 g H * 1 mol/1 g = 7.53 mol H

Divide all the moles by the smallest amount which is 3.725835 mol.

B: 3.725835/3.725835 = 1
N: 3.72857/3.725835 = 1
H: 7.53/3.725835 = 2

Therefore, the empirical formula is BNH₂.

8 0

3 years ago

A body travels 10 meters during the first 5 seconds of its travel, and it travels a total of 30 meters over the first 10 seconds

Mariulka [41]

Answer:

$\large \boxed{\text{C. 4 m/s}}$

Explanation:

At 5 s the body has travelled 10 m.

Between 5 s and 10 s, the body reached 30 m.

Distance travelled = 30 m - 10 m = 20 m

Time = 10 s - 5 s = 5 s

$\text{Speed} = \dfrac{\text{ distance}}{\text{time}} = \dfrac{\text{20 m}}{\text{5 s}} = \textbf{4 m/s}\\\\\text{The average speed between 5 s and 10 s is $\large \boxed{\textbf{4 m/s}}$}$

4 0

3 years ago

How can understanding atomic light help astronomers determine what planets are composed of?

GuDViN [60]

The most common method astronomers use to determine the composition of stars, planets, and other objects is spectroscopy. This process utilizes instruments with a grating that spreads out the light from an object by wavelength. This spread-out light is called a spectrum. Every element has a unique fingerprint that allows researchers to determine what it is made of.

The fingerprint often appears as the absorption of light. Every atom has electrons, and these electrons like to stay in their lowest-energy levels. But when photons carrying energy hit an electron, they can push it to higher energy levels. This is absorption, and each element’s electrons absorb light at specific wavelengths related to the difference between energy levels in that atom. But the electrons want to return to their original levels, so they don’t hold onto the energy for long. When they emit the energy, they release photons with exactly the same wavelengths of light that were absorbed in the first place. An electron can release this light in any direction, so most of the light is emitted in directions away from our line of sight. Therefore, a dark line appears in the spectrum at that particular wavelength.

Because the wavelengths at which absorption lines occur are unique for each element, astronomers can measure the position of the lines to determine which elements are present in a target. The amount of light that is absorbed can also provide information about how much of each element is present.

5 0

3 years ago

If 27 ml of 6.0 m h2so4 was spilled, what is the minimum mass of nahco3 that must be added to the spill to neutralize the acid?

katrin [286]

The minimum mass of NaHCO3 that must be added to the spill to neutralize the acid is 27.216 grams

<h3>calculation </h3>

write the balanced chemical equation

2NaHCO3 +H2SO4 → Na2SO4 +2H2O +2CO2

find the moles of H2SO4 = molarity x volume in liters

volume in liters = 27/1000=0.027 l

moles is therefore= 0.027 x6=0.162 moles

by use of mole ratio of NaHCO3: H2SO4 which is 2:1 the moles of NaHCO3=0.162 x2=0.324 moles

mass of NaHCO3= moles of NaHCO3 x molar mass of NaHCO3(84g/mol)

= 84g/mol x 0.324=27.216 grams

8 0

4 years ago

Read 2 more answers