Hello :
<span> sin 2x = sin x and 0 ≤ x ≤ 2π.
all solutions :
2x= x +2k</span>π or x= π -x +2kπ ..... k in : Z
x = 2kπ or : x = π/2 + kπ
but :
<span>0 ≤ x ≤ 2π
</span><span>all values of x such that sin 2x = sin x and 0 ≤ x ≤ 2π are :
</span>k = 0 : x=0 , x= π/2
k=1 : x=2 π , x=3π/2
Answer:
Choice D is correct answer.
Step-by-step explanation:
We have given two function.
f(x) =2ˣ+5x and g(x) = 3x-5
We have to find the addition of given two function.
(f+g)(x) = ?
The formula to find the addition, we have
(f+g)(x) = f(x) + g(x)
Putting given values in above formula, we have
(f+g)(x) = (2ˣ+5x)+(3x-5)
(f+g)(x) = 2ˣ+5x+3x-5
Adding like terms, we have
(f+g)(x) = 2ˣ+8x-5 which is the answer.
Answer:
s
sStep-by-step explanation:
Answer:
The amount invested at 10% rate is $ 2200
Step-by-step explanation:
Given as :
The total amount earn by student = $6500
The total interest received at the end of year = $607
Let the amount invested at 10% rate = $x
So, The amount invested at 9% rate = ($6500 - $x)
Let the time for which money invested = 1 year
<u>Now from Simple Interest method :</u>
SI =
Or, SI_1 + SI_2 =
+
Or, SI_1 + SI_2 = 
Or, $607 × 100 = 10x + (6500-x) × 9
Or, $60700 = 10x- 9x + 58500
Or, $60700 - $58500 = x
Or , 2200 = x
∴ x = 2200
So, The amount invested at 10% rate = $x = $ 2200
Hence The amount invested at 10% rate is $ 2200 Answer