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NeTakaya
3 years ago
6

Find ƒ–1 for the function ƒ(x) = (x – 10)3 + 4.

Mathematics
1 answer:
RoseWind [281]3 years ago
4 0

Answer:

x=-69/7

Step-by-step explanation:

f (-1) f (x)=(x-10) 3+4

-1=(x-10) 3+4

-1=(x-10) 7

You will multiply 7 by (x-10)

-1=7x-70

Well move the-1 to the right hand side which will become+1 and move the+7x to the left hand side which will become -7x

-7x=-70+1

-7x=-69

So you will divide both sides by-7

-7x/7=-69/7

x=-69/7

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Hunter had 16 jars of paint. He used 2 of them on a painting. He bought 8 more jars. Then, he used some of jars to make another
san4es73 [151]

Answer:

hunter used 5 jars i believe

4 0
3 years ago
Read 2 more answers
Determine the equation of the line passing through (4,-2) and (6,5). Write the line in standard form
S_A_V [24]
Based on the question the equation I generated was y= 3.5x -12.5, hope this helps <3
8 0
3 years ago
The performance of a cyclist in a race is affected by whether it rains or not that day. The probability the cyclist crashes is 5
ZanzabumX [31]

To solve this problem, we have to consider the fact that if the probability that the cyclist may crash due to some circumstance. The probability the cyclist doesn't crash at any given day is 3/8

<h3>Probability</h3>

The probability the cyclist crash when it's wet or dry will be the

P = P_w_e_t * P_d_r_y

  • P(wet) = 5/8
  • P(dry = 1/8

The probability the cyclist crash on any given day is

P = \frac{5}{8}*\frac{1}{8} =\frac{5}{64}

we can subtract 1 from the value above to find the probability the cyclist doesn't crash at any given day

P = 1 - \frac{5}{64} \\P=\frac{3}{8}

The probability the cyclist doesn't crash at any given day is 3/8

Learn more on probability here;

brainly.com/question/24756209

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4 0
2 years ago
Each square represents one square foot. Estimate the area of the figure below.
JulijaS [17]
The estimated area of the figure is 36 square foot.
5 0
3 years ago
Find the shaded region.
pashok25 [27]

Answer:

Step-by-step explanation:

let the side of outer square=2x

then x²+x²=(20√2)²

2x²=800

x²=400

x=√400=20 in

2x=2×20=40 in

area of outer square=40²=1600 in²

area of inner square=(20√2)²=800 in²

area of shaded  region A=1600-800=800 in²

8 0
4 years ago
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