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3 years ago

P2-16p+48=0 Please solve this math problem

Mathematics

1 answer:

Leni [432]3 years ago

8 0

Answer:

( p - 4 ) ( p - 12 ) = 0

Step-by-step explanation:

To factor this equation, let's apply the quadratic formula.

p^2 - 16p + 48 = 0

Let a = 1, b = -16, c = 48

[-b +/- sqrt(b^2 - 4(a)(c))] / 2 (a)

[- (-16) +/- sqrt( (-16)^2 - 4(1)(48)) ] / 2 (1)

= [ 16 +/- sqrt( 256 - 192) ] / 2

= [ 16 +/- sqrt(64) ] / 2

= [16 +/- 8] / 2

p = (16 + 8) / 2 ; p = (16 - 8) / 2

p = 24 / 2 ; p = 8 / 2

p = 12 ; p = 4

Hence, this equation factors into the following:

( p - 4 ) ( p - 12 ) = 0

Cheers.

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Answer:

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Step-by-step explanation:

Step 1: Determine how much money both have

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Rich: 5 + 3x

Step 2: Write an equation and solve

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Step 3: Solve the equation

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3 years ago

Charlie’s portfolio has an expected annual return at 10%, with an annual standard deviation at 12%. Assume his investment return

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Answer:

There is a 34.13% probability that the actual return will be between the mean and one standard deviation above the mean.

Step-by-step explanation:

This is problem is solving using the Z-score table.

The Z-score of a measure measures how many standard deviations above/below the mean is a measure. Each Z-score has a pvalue, that represents the percentile of a measure.

What is the probability that the actual return will be between the mean and one standard deviation above the mean?

One measure above the mean is $Z = 1$

The mean is $Z = 0$

This means that this probability is the pvalue of $Z = 1$ subtracted by the pvalue of $Z = 0$ .

$Z = 1$ has a pvalue of 0.8413.

$Z = 0$ has a pvalue of 0.50.

This means that there is a 0.8413-0.50 = 0.3413 = 34.13% probability that the actual return will be between the mean and one standard deviation above the mean.

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3 years ago

the cube shown is composed of 27 unit cubes. The top and bottom faces of the cube are painted red, and the other faces are paint

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Answer:

There are 16 blocks that are painted with 2 colors which are red and blue and 1 block that isn't painted

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Answer:

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Step-by-step explanation:

we know that

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The lateral area of a cylinder is given by the formula

$LA=\pi Dh$

we have

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substitute

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3 years ago

Arrange the following numbers in increasing order: \begin{align*} A &= \frac{2^{1/2}}{4^{1/6}}\\ B &= \sqrt[12]{128}\vph

prisoha [69]

Answer:

The order is "D, B, A, E, C".

Step-by-step explanation:

The numbers are as follows:

$A=\frac{2^{1/2}}{4^{1/6}}\\\\B = \sqrt[12]{128}\\\\C=(\frac{1}{8^{1/5}})^{2}\\\\D = \sqrt{\frac{4^{-1}}{2^{-1}\cdot 8^{-1}}}\\\\E = \sqrt[3]{2^{1/2}}\cdot 4^{-1/4}$

Simplify the value of A, B, C, D and E as follows:

$A=\frac{2^{1/2}}{4^{1/6}}=\frac{2^{1/2}}{2^{2/6}}=\frac{2^{1/2}}{2^{1/3}}=2^{1/2-1/3}=2^{1/6}=1.1225\\\\B = \sqrt[12]{128}=(128)^{1/12}=(2^{7})^{1/12}=2^{7/12}=1.4983\\\\C=(\frac{1}{8^{1/5}})^{2}=(\frac{1}{(2^{3})^{1/5}})^{2}=(\frac{1}{2^{3/5}})^{2}=\frac{1}{2^{3/5\times2}}=\frac{1}{2^{6/5}}=2^{-6/5}=0.4353\\\\D = \sqrt{\frac{4^{-1}}{2^{-1}\cdot 8^{-1}}}=\sqrt{\frac{2^{-2}}{2^{-1}\cdot 2^{-3}}}=\sqrt{2^{-2+1+3}}=2\\\\E = \sqrt[3]{2^{1/2}}\cdot 4^{-1/4}= (2^{1/2})^{1/3}\cdot 2^{-2/4}=2^{-1/3}=0.7937$

Arrange the following numbers in increasing order as follows:

D > B > A > E > C

Thus, the order is "D, B, A, E, C".

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