Answer:
The value of c = -0.5∈ (-1,0)
Step-by-step explanation:
<u>Step(i)</u>:-
Given function f(x) = 4x² +4x -3 on the interval [-1 ,0]
<u> Mean Value theorem</u>
Let 'f' be continuous on [a ,b] and differentiable on (a ,b). The there exists a Point 'c' in (a ,b) such that

<u>Step(ii):</u>-
Given f(x) = 4x² +4x -3 …(i)
Differentiating equation (i) with respective to 'x'
f¹(x) = 4(2x) +4(1) = 8x+4
<u>Step(iii)</u>:-
By using mean value theorem


8c+4 = -3-(-3)
8c+4 = 0
8c = -4

c ∈ (-1,0)
<u>Conclusion</u>:-
The value of c = -0.5∈ (-1,0)
<u></u>
Line joining (-3, -1) and (1/2, 2)
Point point form for a line is
(c-a)(y-b) = (d-b)(x-a)
(1/2 - - 3)(y - -1) = (2 - -1)(x - -3)
(7/2)(y+1)=3(x+3)
7(y+1)=6(x+3)
7 - 6(3) = 6x - 7y
6x - 7y = -11
Answer: second choice, 6x - 7y = -11
We need to find the other base also in order for us to find out what the area of this is.