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3 years ago

What is the next number 3,6,4,8,6,12,10

Mathematics

1 answer:

Veseljchak [2.6K]3 years ago

8 0

The next ten numbers will be 20,18,36,34,68,66,132,130,260,258. Hope this helps.

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CAN SOMEONE ANSWER THIS PLEASEEE AND THANK YOU!

Olegator [25]

Answer:

A:400

Step-by-step explanation:

Hopefully this helps.

4 0

3 years ago

Please Help, This is a mathematical question, which I'm confused on.

Goryan [66]

T would be 72 because 2x2=4 and 4x18=72

4 0

3 years ago

Read 2 more answers

Quadrilateral ABCD is a rectangle. If AG = -7j + 7 and DG = 5j + 43, find BD

Kaylis [27]

BD = 56

Step-by-step explanation:

Step 1: In rectangle, the diagonals are congruent and bisect each other.

So, AC = BD

⇒AG + GC = BG + GD

⇒AG + AG = GD + GD

⇒ 2AG = 2GD

⇒AG = GD

⇒ –7j + 7 = 5j + 43

⇒–7j – 5j = 43 – 7

⇒–12j = 36

⇒j = –3

Step 2: BD = 2DG

BD = 2(5j + 43)

= 2(5 (–3) + 43)

= 2(–15 + 43)

= 2 × 28

= 56

Hence, BD = 56.

4 0

3 years ago

Find the minimum sample size when we want to construct a 90% confidence interval on the population proportion for the support of

kogti [31]

N = 73
Hope this helps

4 0

3 years ago

Three cards are drawn from a standard deck of 52 cards without replacement. Find the probability that the first card is an ace,

MrRissso [65]

Answer:

$4.82\cdot 10^{-4}$

Step-by-step explanation:

In a deck of cart, we have:

a = 4 (aces)

t = 4 (three)

j = 4 (jacks)

And the total number of cards in the deck is

n = 52

So, the probability of drawing an ace as first cart is:

$p(a)=\frac{a}{n}=\frac{4}{52}=\frac{1}{13}=0.0769$

At the second drawing, the ace is not replaced within the deck. So the number of cards left in the deck is

$n-1=51$

Therefore, the probability of drawing a three at the 2nd draw is

$p(t)=\frac{t}{n-1}=\frac{4}{51}=0.0784$

Then, at the third draw, the previous 2 cards are not replaced, so there are now

$n-2=50$

cards in the deck. So, the probability of drawing a jack is

$p(j)=\frac{j}{n-2}=\frac{4}{50}=0.08$

Therefore, the total probability of drawing an ace, a three and then a jack is:

$p(atj)=p(a)\cdot p(j) \cdot p(t)=0.0769\cdot 0.0784 \cdot 0.08 =4.82\cdot 10^{-4}$

4 0

3 years ago