The number of rounds that can be played is given by the product of three
and the least number of tokens a player has at the start.
<h3>Response;</h3>
<h3>Reasons for arriving at the above value;</h3>
A round is when the player with the most tokens gives one token to each of the other players, and one placed in the discard pile, we have;
<h3>First three round</h3>
17 - 3 = 14
16 + 1 = 17
15 + 1 = 16
17 - 3 = 14
14 + 1 = 15
16 + 1 = 17
17 - 3 = 14
14 + 1 = 15
15 + 1 = 16
The above values follow a number series such that we have;
<h3>Fourteenth three rounds</h3>
4 - 3 = 1
2 + 1 = 3
3 + 1 = 4
4 - 3 = 1
1 + 1 = 2
3 + 1 = 4
4 - 3 = 1
2 + 1 = 3
1 + 1 = 2
<h3>Fifteenth three rounds</h3>
3 - 3 = 0
1 + 1 = 2
2 + 1 = 3
3 - 3 = 0
0 + 1 = 1
2 + 1 = 3
3 - 3 = 0
0 + 1 = 1
1 + 1 = 2
Therefore, after the fifteenth three rounds, which is 15 × 3 = <u>45 rounds</u> Ava runs out of token, ending the game.
Learn more about number series here:
brainly.com/question/4163549
Answer:397.1....i think
Step-by-step explanation:
I hope this helps you
x^2 =125/4-121/4-11
x^2=4/4-11
x^2=1-11
x^2= -10
x= i.square root of 10
The <em>simple annual interest</em> rate for the $ 525 loan is equal to 46.35 %.
<h3>What is the interest rate behind a pay back?</h3>
In this situation we assume that the loan does not accumulate interests continuously in time. Hence, the <em>interest</em> rate for paying the loan back 75 days later is:
575 = 525 · (1 + r/100)
50 = 525 · r /100
5000 = 525 · r
r = 9.524
The loan has an <em>interest</em> rate of 9.524 % for 75 days. <em>Simple annual interest</em> rate is determine by rule of three:
r' = 9.524 × 365/75
r' = 46.350
The <em>simple annual interest</em> rate for the $ 525 loan is equal to 46.35 %.
To learn more on interests: brainly.com/question/26457073
#SPJ1
Answer:
Simplify 3(x+1)−5.
3x−2=3x−2
Move all terms containing x to the left side of the equation.
−2=−2 Since −2=−2 , the equation will always be true for any value of x
All real numbers
The result can be shown in multiple forms.
All real numbers
Interval Notation:
(−∞,∞)
Option2 : infinite solutions
Step-by-step explanation:
