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Inessa05 [86]
3 years ago
9

Keith needed 100 feet of rope to make a border at a fundraising event his youth grew was holding at a local park. Someone gave h

im a rope and told him it was 30 meters long. Is the rope long enough?
Mathematics
2 answers:
Klio2033 [76]3 years ago
8 0

Answer:

No

Step-by-step explanation:

because 30 meters is equivalent to 98 feet, which is not 100 feet

Alexeev081 [22]3 years ago
6 0
The rope is not long enough a meter is roughly 3 feet 3 inches totalling out to 98 feet and a few inches
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Find the domain of h(x)=x-3/x^3-36x
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There is some ambiguity here which could be removed by using parentheses.  I'm going to assume that you actually meant:

               x-3

h(x) = ---------------

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To determine the domain of this function, factor the denominator:

x^3 - 36x = x(x^2 - 36) = x(x-6)(x+6)

The given function h(x) is undefined when the denominator = 0, which happens at {-6, 0, 6}.

Thus, the domain is "the set of all real numbers not equal to -6, 0 or 6."

Symbolically, the domain is   (-infinity, -6) ∪ (-6, 0) ∪ (0, 6) ∪ (6, +infinity).

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3 years ago
A rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1
Korvikt [17]

Answer:

Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

Counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Step-by-step explanation:

Given  : rectangle has vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4)

To find :  transformed according to the rule 90º , what is the location of q?

Solution : we have given that

vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4).

By the rule of 90º rotation clock wise rule : (x ,y ) →→ ( y , -x )

90º rotation counter clock wise rule : (x ,y ) →→ ( -y , x ).

Then   Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Therefore, Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

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Step-by-step explanation:

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