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ryzh [129]
3 years ago
8

Mark says that the number square root two is irrational number because he can write it as a fraction square root two over one is

more correct why or why not
Mathematics
1 answer:
Elan Coil [88]3 years ago
6 0

Answer:

Step-by-step explanation:

A rational number are numbers that can be expressed as as fraction. They can be expressed as a ratio of two integers. An irrational is quite the opposite.  An irrational number cannot be expressed as a ratio of two integers.

Taking square root of two as an example;

√2 cannot be expressed as a ratio of two integers because the result will always be a decimal. If expressed as √2/1, it is still not a rational number because of the square root of 2 at the numerator. Square root of 2 is not an integer even though 1 is an integer.

Mark is wrong because √2 is irrational and it is irrational because it cannot be expressed as a ratio of two integers <em>not due to the fact that he can write it as a fraction.</em>

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The equation y - 9 + 9 = 17 + 9 shows which property of equality?
BARSIC [14]

Answer:

No maim

Step-by-step explanation:

It does not

7 0
3 years ago
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Wpisz odpowiednie liczby: 1 cm2=...........mm2 9 cm2=...........mm2 5,2 cm2=............mm2 1 dm2 =...........cm2 17dm2=........
Tomtit [17]

Answer:

1 cm^2 = 100 mm^2

9 cm^2 = 900 mm^2

5.2 cm^2 = 520 mm^2


1 dm^2 = 100 cm^2

17 dm^2 = 1700 cm^2

4.3 dm^2 = 430 cm^2


1 m^2 = 10000 cm^2

7 m^2 = 70000 cm^2

2.5 m^2 = 25000 cm^2


1 km^2 = 1000000 m^2

50 km^2 = 50000000 m^2

8.5 km^2 = 8500000 m^2

Step-by-step explanation:

1 cm = 10 mm

1 cm^{2} = 10×10 mm^{2} = 100 mm^{2}

9 cm^{2} = 9×100 mm^{2} = 900 mm^{2}

5.2  cm^{2} = 5.20×100 mm^{2} = 520 mm^{2}


1 dm = 10 cm

1 dm^{2} = 10×10 cm^{2} = 100 cm^{2}

17 dm^{2} = 17× 100 cm^{2} = 1700 cm^{2}

4.3 dm^{2} = 4.3 × 100 cm^{2} = 430 cm^{2}


1 m = 100 cm

1 m^{2} = 100×100 cm^{2} = 10000 cm^{2}

7 m^{2} = 7×10000  cm^{2} = 70000 cm^{2}

2.5 m^{2} = 2.5×10000 cm^{2} = 25000 cm^{2}


1 km = 1000 m

1 km^{2} = 1000×1000 m^{2} = 1000000 m^{2}

50 km^{2} = 50×1000000 m^{2} = 50000000 m^{2}

8.5 km^{2} = 8.5×1000000 m^{2} = 8500000 m^{2}

3 0
4 years ago
Marie pays $2.50 for 5 pecils. Use the drop down menu to explain how to determine and use constant of proportionality, in dollar
stiks02 [169]

Answer:

$0.5

Step-by-step explanation:

Given data

Cost of 5 pencils= $2.50

Required

The cost per pencil

The cost per pencil is

Cost of 5 pencils divided by 5

=2.5/5

=$0.5

This is the constant of proportionality

For any number of pencils x

The cost is

Cost =0.5x

Hence the cost of one pencil is $0.5

5 0
3 years ago
Megan is the manager of a computer shop she organises a sale with 18% off all tables Megan changes the price of own table from £
Dominik [7]

Answer:

this is easy. all you have to do is figure out what 18% of 389 is and then subtract that answer from 389. the easy trick i use is to make a fraction with the numerator being a question mark and the denominator being 389 (displayed below). then you would make a second fraction with 18 as the numerator and 100 being the denominator (displayed below). you would then multiply 389 with 18 and divide by 100 to get the numerator of the first fraction (which is 70.02). now you subtract 70.02 from 389 (being 318.98). this would mean that Megan has not done the math correctly.

Step-by-step explanation:

?/389 = 18/100

389 x 18 = 7002

100/7002 = 70.02

389 - 70.02 = 318.98

3 0
3 years ago
Use the given values of n and p to find the minimum usual value μ - 2σ and the maximum usual value μ + 2σ.
mart [117]

Answer:

\mu -2\sigma = 915.428 - 2* 22.87=869.69

\mu +2\sigma = 915.428 + 2* 22.87=961.17

And the best option would be:

4. Minimum: 869.69; maximum: 961.17

Step-by-step explanation:

We can assume that the variable of interst X is distributed with a binomial distribution and we can use the normal approximation.

For this case the mean would be given by:

E(X) = np = 2136 *(\frac{3}{7})= 915.428

And the standard deviation would be:

\sigma = \sqrt{2136*(\frac{3}{7}) (1-\frac{3}{7})} =22.87

And if we find the limits we got:

\mu -2\sigma = 915.428 - 2* 22.87=869.69

\mu +2\sigma = 915.428 + 2* 22.87=961.17

And the best option would be:

4. Minimum: 869.69; maximum: 961.17

5 0
3 years ago
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