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dusya [7]
3 years ago
5

One fifth of the people living in a town are 6'0" or taller than 6'0", and one sixth of the people living in the same town are 5

'0" or shorter than 5'0". What fraction of the people of the town measure between 5'0" and 6'0"?
19/30

11/30

29/30

21/30
Mathematics
1 answer:
astra-53 [7]3 years ago
7 0
1/5 of people= 6
1/6 of people= 5
6+5= 11
30-11= 19
19/30 people measure 5’0” and 6’0”
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Doesn’t anyone know the answer to this
cricket20 [7]
D. 8°
Explanation: A triangle is always 180° and we know of two points is 50° and 80°, the other must be 60, the 60° is cut in half so if it’s 30° the other side must be thirty. DBC Is 30+50
5 0
3 years ago
Help plz I've been stuck
stepladder [879]

Answer:

The answer is D. (\frac{1}{5} )^{2}

Step-by-step explanation:

5^{4} *(5^{-3} )^{2}

simplify the expression by multiplying

5^{4} *5^{-6}

calculate the product

5^{-2}

express with a positive exponent using a^{-n} =\frac{1}{a^{n} }

\frac{1}{5^{2} }

6 0
3 years ago
Read 2 more answers
Solve the given triangles by finding the missing angle and other side lengths.
coldgirl [10]

Answer:

  1. a ≈ 27.65; B = 28°; c ≈ 19.17
  2. a ≈ 163.30; B = 120°; c ≈ 59.77
  3. A = 13°; b ≈ 0.3874; c ≈ 1.3737

Step-by-step explanation:

As long as you're seeking outside help, the use of a suitable tool is appropriate. Many graphing calculators, apps, and web sites are available for solving triangles.

__

Here, you're given two angles and a side. The third angle is the difference from 180° of the sum of the other two. For example, in the first problem, ...

  B = 180° -A -C = 28°

The missing sides are found using the law of sines. Since you are given a side, use that as the reference, and its opposite angle as the reference angle. Then you have ...

  side = sin(opposite angle)×<em>((reference side)/sin(reference angle))</em>

Note that the factor in italics remains the same for both remaining sides.

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In the first problem, this becomes ...

  a = sin(112°)·14/sin(28°) ≈ 27.65

  c = sin(40°)·14/sin(28°) ≈ 19.17

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The remaining problems are worked in similar fashion.

_____

<em>Comment on triangle solutions</em>

These are straightforward because you're given two angles. If you're given two sides and an angle, the solution method varies depending on which angle you're given (opposite the long side, the short side, or the unknown side). In the last case, the law of cosines is involved. In the second case, there are likely two solutions. Once you have two angles, you can proceed as above.

8 0
3 years ago
Read 2 more answers
Pleaseee help if you can!!!!!!!
REY [17]

Answer:

85 degrees

Step-by-step explanation:

Theses angles are the same because its parallell

3 0
3 years ago
Can someone pls help me on 4 and 5
never [62]

Answer (4):

a=ub/k because

u=ak/b   (starting equation)

ub=ak    (multiply b to both sides)

a=ub/k   (divide both sides by k)

Answer (6)

x=g+c-y because

g=x-c+y  (starting equation)

x+y=g+c (add c to both sides)

x=g+c-y  (subtract y from both sides)

5 0
3 years ago
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