7 + 3 = 10 those are the 2 addens
Answer:
6
Step-by-step explanation:
Using Euclid's algorithm, we divide the larger by the smaller. If the remainder is zero, the divisor is the GCF. Otherwise, we replace the larger with the remainder and repeat.
18 ÷ 12 = 1 r 6
12 ÷ 6 = 2 r 0 . . . . the GCF is 6
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You can also factor the numbers and see what the common factors are.
18 = 2·3·3
12 = 2·2·3
The common factors are 2·3 = 6.
In the factorizations, we see 2 to powers of 1 and 2, and we see 3 to powers of 1 and 2. The GCF is the product of the common factors to their lowest powers: (2^1)(3^1) = (2)(3) = 6
The product of A and B matrix will be option D; BA = ![\left[\begin{array}{ccc}16&10&39\\-32&-30&-18\\-6&-6&-19\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D16%2610%2639%5C%5C-32%26-30%26-18%5C%5C-6%26-6%26-19%5Cend%7Barray%7D%5Cright%5D)
.
<h3>What is the multiplication of matrix?</h3>
If ![A = \left[\begin{array}{ccc}-2&-4&2\\5&1&5\\-1&-3&-4\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%26-4%262%5C%5C5%261%265%5C%5C-1%26-3%26-4%5Cend%7Barray%7D%5Cright%5D)
and ![B = \left[\begin{array}{ccc}2&3&-5\\5&-4&2\\-1&-1&3\end{array}\right]](https://tex.z-dn.net/?f=B%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%26-5%5C%5C5%26-4%262%5C%5C-1%26-1%263%5Cend%7Barray%7D%5Cright%5D)
then,
BA = ![\left[\begin{array}{ccc}2&3&-5\\5&-4&2\\-1&-1&3\end{array}\right] \left[\begin{array}{ccc}-2&-4&2\\5&1&5\\-1&-3&-4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%26-5%5C%5C5%26-4%262%5C%5C-1%26-1%263%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%26-4%262%5C%5C5%261%265%5C%5C-1%26-3%26-4%5Cend%7Barray%7D%5Cright%5D)
BA =
Hence, the product of A and B matrix will be option D; BA = .
Learn more about matrix here;
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Answer:
1. 44h + 12g
2. 9ab + 13a
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