Find the locus of a point P such that its ordinate is equal to the abscissa. Hence required equation of the locus of point P is y = 5x + 9. Hence required equation of the locus of point P is x = 2y + 3.
STEP 1- since 6 doesn't contain the variable to solve for move it to the right side of the equation by subtracting 6 from both sides
X^2-8X=-6
STEP 2- create a trinomial square on the left side of the equation find the value that is equal to the square of half of b the coefficient of x
(b/2)^2 =(-4)^2
STEP 3- add the term to each side of the equation
x^2-8x+(-4)^2=-6=(-4)
STEP 4- simplify the equation
x^2-8x+16=10
STEP 5- factor the perfect trinomial square into (x-4)^2
(x-4)^2=10
STEP 6-solve the equation for x
x=4= square root of 10
Answer:
y = -3x - 12
Step-by-step explanation:
Lines that are parallel have the same gradient.
Therefore using the point (-2,-6) you can make your own equation.
-6 will be y, -2 will be x
All you have to do is find the y-intercept which is C in <em>y</em><em>=</em><em>mx</em><em>+</em><em>c</em>
-6 = -3(-2) + c
-6 = 6 + c
-12 = c
Therefore;
<u>y = -3x - 12</u>
