Answer:
The <em>p</em>-value is 0.809.
Step-by-step explanation:
In this case we need to perform a significance test for the standard deviation.
The hypothesis is defined as follows:
<em>H</em>₀: <em>σ</em>₀ = 4 vs. <em>Hₐ</em>: <em>σ</em>₀ ≤ 4
The information provided is:
<em>n</em> = 9
<em>s</em> = 3
Compute the Chi-square test statistic as follows:
The test statistic value is 4.5.
The degrees of freedom is:
df = n - 1
= 9 - 1
= 8
Compute the <em>p</em>-value as follows:
*Use a Chi-square table.
Thus, the <em>p</em>-value is 0.809.
Answer:
6÷41 equals 0.14634146341
6÷21 equals 0.28571428571
6÷43 equals 0.13953488372
6÷37 equals 0.16216216216
6÷20 equals 0.3
Step-by-step explanation:
Hope this helps
Answer:
The probably genotype of individual #4 if 'Aa' and individual #6 is 'aa'.
Step-by-step explanation:
In a non sex-linked, dominant trait where both parents carry and show the trait and produce children that both have and don't have the trait, they would each have a genotype of 'Aa' which would produce a likelihood of 75% of children that carry the dominant traint and 25% that don't. Since the child of #1 and #2, #5, does not exhibit the trait, nor does the significant other (#6), then they both must have the 'aa' genotype. However, since #4 displays the dominant trait received from the parents, it is more likely they would have the 'Aa' genotype as by the punnet square of 'Aa' x 'Aa', 50% of their children would have the 'Aa' phenotype.
Answer:
29504.5624608
Step-by-step explanation:
3.174 is closer to 3.2 because, when rounding, 0.07 rounds up to 0.2.
