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Rzqust [24]
3 years ago
5

Need help (8th grade math)

Mathematics
2 answers:
True [87]3 years ago
3 0

Slope= rise/run

=y2-y1/x2-x1

3-1/8-7

2/1

Slope=2

belka [17]3 years ago
3 0

Answer:

2

Step-by-step explanation:

- use the equation:

m=y^2-y^1/x^2-x^1

- pick any two points:

m= -1+3/6-5

- solve:

m= 2/1

FINAL ANSWER:

2

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A baseball is thrown without any spin. Would you consider the baseball to be in motion?
liq [111]

Answer:

yes

Step-by-step explanation:

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3 years ago
X = 0.19
Luda [366]

Step-by-step explanation:

.19 = 19/100

.864 = 86.4/100

.5348 = 53.48 /100

I multiplied the decimal by 100 to get what it was before which is the same as moving two decimal places to the right and divided by 100

if any confusion ask

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2 years ago
Read 2 more answers
Carrie has 2 meters of ribbon. She cuts off pieces of ribbon that are 5/10 meter, 1/10 meter, and 7/10 meter. How long is the re
vekshin1

Answer:

\frac{7}{10}

Step-by-step explanation:

Carrie has 2 meters of ribbon. She cuts off pieces of ribbon that are 5/10 meter, 1/10 meter, and 7/10 meter

Lets add all the cut of pieces and subtract it from 2 meters

\frac{5}{10} +\frac{1}{10}+\frac{7}{10}=\frac{13}{10}

Now we subtract 13/10 from 2 meters

2 - \frac{13}{10}

To subtract , make the denominator same

\frac{2*10}{1*10} - \frac{13}{10}=\frac{20}{10} - \frac{13}{10}=\frac{7}{10}

7/10 meter is the remaining piece of ribbon

8 0
3 years ago
PLEASE HELP ! Suppose another company offers a special
kolezko [41]

The special is cheaper than Bella's price. Then the correct option is B.

<h3>What is the linear system?</h3>

A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.

Suppose another company offers a special banquet price of $4,000 for 150 people.

Then the special is cheaper than Bella's price.

Then the correct option is B.

More about the linear system link is given below.

brainly.com/question/20379472

#SPJ1

5 0
2 years ago
A random variable X with a probability density function () = {^-x &gt; 0
Sliva [168]

The solutions to the questions are

  • The probability that X is between 2 and 4 is 0.314
  • The probability that X exceeds 3 is 0.199
  • The expected value of X is 2
  • The variance of X is 2

<h3>Find the probability that X is between 2 and 4</h3>

The probability density function is given as:

f(x)= xe^ -x for x>0

The probability is represented as:

P(x) = \int\limits^a_b {f(x) \, dx

So, we have:

P(2 < x < 4) = \int\limits^4_2 {xe^{-x} \, dx

Using an integral calculator, we have:

P(2 < x < 4) =-(x + 1)e^{-x} |\limits^4_2

Expand the expression

P(2 < x < 4) =-(4 + 1)e^{-4} +(2 + 1)e^{-2}

Evaluate the expressions

P(2 < x < 4) =-0.092 +0.406

Evaluate the sum

P(2 < x < 4) = 0.314

Hence, the probability that X is between 2 and 4 is 0.314

<h3>Find the probability that the value of X exceeds 3</h3>

This is represented as:

P(x > 3) = \int\limits^{\infty}_3 {xe^{-x} \, dx

Using an integral calculator, we have:

P(x > 3) =-(x + 1)e^{-x} |\limits^{\infty}_3

Expand the expression

P(x > 3) =-(\infty + 1)e^{-\infty}+(3+ 1)e^{-3}

Evaluate the expressions

P(x > 3) =0 + 0.199

Evaluate the sum

P(x > 3) = 0.199

Hence, the probability that X exceeds 3 is 0.199

<h3>Find the expected value of X</h3>

This is calculated as:

E(x) = \int\limits^a_b {x * f(x) \, dx

So, we have:

E(x) = \int\limits^{\infty}_0 {x * xe^{-x} \, dx

This gives

E(x) = \int\limits^{\infty}_0 {x^2e^{-x} \, dx

Using an integral calculator, we have:

E(x) = -(x^2+2x+2)e^{-x}|\limits^{\infty}_0

Expand the expression

E(x) = -(\infty^2+2(\infty)+2)e^{-\infty} +(0^2+2(0)+2)e^{0}

Evaluate the expressions

E(x) = 0 + 2

Evaluate

E(x) = 2

Hence, the expected value of X is 2

<h3>Find the Variance of X</h3>

This is calculated as:

V(x) = E(x^2) - (E(x))^2

Where:

E(x^2) = \int\limits^{\infty}_0 {x^2 * xe^{-x} \, dx

This gives

E(x^2) = \int\limits^{\infty}_0 {x^3e^{-x} \, dx

Using an integral calculator, we have:

E(x^2) = -(x^3+3x^2 +6x+6)e^{-x}|\limits^{\infty}_0

Expand the expression

E(x^2) = -((\infty)^3+3(\infty)^2 +6(\infty)+6)e^{-\infty} +((0)^3+3(0)^2 +6(0)+6)e^{0}

Evaluate the expressions

E(x^2) = -0 + 6

This gives

E(x^2) = 6

Recall that:

V(x) = E(x^2) - (E(x))^2

So, we have:

V(x) = 6 - 2^2

Evaluate

V(x) = 2

Hence, the variance of X is 2

Read more about probability density function at:

brainly.com/question/15318348

#SPJ1

<u>Complete question</u>

A random variable X with a probability density function f(x)= xe^ -x for x>0\\ 0& else

a. Find the probability that X is between 2 and 4

b. Find the probability that the value of X exceeds 3

c. Find the expected value of X

d. Find the Variance of X

7 0
2 years ago
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