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GaryK [48]
2 years ago
12

0.2 is 10 times as much as ?? and

{1}{10} " alt=" \frac{1}{10} " align="absmiddle" class="latex-formula"> of ??
Mathematics
1 answer:
leva [86]2 years ago
6 0
0.2 is 10 times as much of... well you must do the opposite of what it says... well, times means to multiply and the opposite of multiplying is dividing, 0.2 divided by 10 is 0.02

So... 0.2 is 10 times as much as 0.02

Now, 0.2 is 1/10 of... well this question shows to divide and we must do the opposite, which is... multiplying 0.2 times 10 is 2

So... 0.2 is 1/10 of 2
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6 0
3 years ago
Please help 25 points and brainliest
-BARSIC- [3]

Answer:

1a. 8

1b. AB & BC

1c. AC

2. \sqrt{52} miles

3. NO

Step-by-step explanation:

1a. AC is your hypotenuse which is C² and BC is B², so we plug it in the equation.

A²+6²=10²

A²+36=100

A²=64

A=\sqrt{64}

A=8

1b. Legs are the two shorter sides, AB & BC, which are 6 & 8 respectively.

1c. The hypotenuse is the longest side AC

2. Make lines that make the graph for a triangle with a line. My graph is linked below. Then counts the points, AC=6, BC=4, then use the pythagorean therom.

6²+4²=X²

36+16=52

\sqrt{52}=X

3. 15²+17²=19²

514=361

not possible

so it is not a right triangle

7 0
2 years ago
Please Help Me! I will give all my point to who ever answers my question!!!
love history [14]

Step-by-step explanation:

The equation that is given is only for the specific place of that object. To find the velocity, you need to take the derivative of the equation. This will give you:

V=2+\frac{1}{2} t

Now, to find the average velocity of this object, plug in the values given to you. It's between the time interval [1, 2] so these are the two numbers you'll plug into the velocity equation. Finding this average is like finding any other average.

So

V(1)=2+\frac{1}{2} (1)\\V(1)=2+\frac{1}{2}=\frac{5}{2}\\V(2)=2+\frac{1}{2}(2)\\V(2)=2+1=3

V_{avg}=\frac{3-\frac{5}{2} }{2-1} \\V_{avg}=\frac{\frac{6}{2}-\frac{5}{2}  }{1} \\V_{avg}=\frac{1}{2}

Average velocity is 0.5 sec

To find instantaneous velocity just find the velocity at time one. Think about the name "instantaneous velocity," it's the velocity in that <u>instant</u>.

We already found this, so I don't need more work (it's displayed above).

The instantaneous velocity when t=1 is 2.5 sec.

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3 years ago
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Answer:

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