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adell [148]
4 years ago
10

A unstretched spring hangs from the ceiling with a length of 0.31 m. a 9.1-kg block is hung from the spring and the spring stret

ches to be 0.50 m long. how long will the spring be if a 3.3-kg block is hung from the spring? for both cases, all vibrations of the spring are allowed to settle down before any measurements are made.
Physics
1 answer:
adoni [48]4 years ago
7 0

As we know that spring force is given by

F = kx

here we know that for the equilibrium of the mass suspended with the spring we have

mg = kx

so now we have

9.1(9.81) = k(0.50 -0.31)

now we have

k = 469.8 N/m

now we have another mass

m = 3.3 kg

again from above equation we have

3.3 (9.81) = 469.8(L - 0.31)

L = 0.38 m

so final length of the spring will be 0.38 m

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The answer would be the Scientific Method.

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7) Germanium, element 32 on the Periodic Table, is shown here. If a proton is added to the nucleus of germanium, what outcome(s)
cestrela7 [59]

Addition of a proton to germanium  will convert it to arsenic (element 33) having different properties.

The atomic number of an atom is the number of protons in the nucleus of the atom. The atomic number serves as the identity of an atom. If the atomic number is changed by adding or removing protons, the identity of that atom changes.

Hence, when a proton is added to germanium, the  atom would become arsenic (element 33) and have different properties.

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3 years ago
Two point charges are brought closer together, increasing the force between them by a factor of 20. By what factor was their sep
olga55 [171]

The separation between them is \frac{r}{\sqrt{20} }

Concept :

If the force increases, distance between charges must decrease. Force is indirectly proportional to the distance squared.

Given,

Two point charges are brought closer together, increasing the force between them by a factor of 20.

Original force is

F = \frac{kq_{1} q_{2} }{r^{2} } -------- ( 1 )

Here, q_{1} , q_{2} are charges and r is the distance between them

New force F' = \frac{kq_{1q_{2} } }{r'^{2} } ----------- (2 )

Divide ( 1 ) and ( 2 )

\frac{F'}{F} = \frac{\frac{kq_{1}q_{2}  }{r'^{2} } }{\frac{kq_{1}_{2}  }{r^{2} } }

20 = \frac{r^{2} }{r'^{2} }

r' = \frac{r}{\sqrt{20} }

Given that force between them are increasing and therefore distance between them decrease by \frac{r}{\sqrt{20} }

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8 0
2 years ago
On a smooth horizontal floor, an object slides into a spring which is attached to another mass that is initially stationary. Whe
saul85 [17]

Answer: (E) Momentum and mechanical energy

Explanation:

 The momentum and the mechanical energy is basically conserved during the given interaction process as the forces on the given system are in the form of internal nature and then the momentum are get conserved.

According to the given question, on the smooth floor when an object are slides by using the spring then the momentum and the mechanical energy are conserved.

The mechanical energy is the combination of both the kinetic and the potential energy that is used for doing some amount of work. Therefore, Option (E) is correct answer.  

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