Initial velocity=u=3m/s
Final velocity=v=10m/s
Time=t=8s




Using second equation of motion





Answer:
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Answer:
The answer is given below
Explanation:
Things provided in the statement:
Pressure <em>P1</em> = 120 kPa and <em>P2</em> = 5.6 MP or 5600 kPa
Power, <em>W</em> = 7 kW
Elevation difference = ∆z = 10 m
Mass of flow = m˙
So potential energy changes may be significant
Specific volume of water V= 0.001 m³/kg
Now putting the values in the formula
Power, <em>W </em>= m˙ x V (<em>P1 - P2</em>) + m˙ x g x ∆z
7 = m˙ x 0.001 (5600 - 120 ) + m˙ x 9.8 x 10 x (1 kJ/kg/ 1000 m^2/s^2)
7 = m˙ x 5.48 + m˙ x 0.098
7 = m ˙x 5.38
m˙ = 7/5.38
So mass flow m˙ = 1.301 kJ/s
Answer:
Potential Difference = 14 V
Explanation:
We are told that when the capacitor plates are charged to a certain voltage, then we have;
ΔV = 14 volts
Now, the battery is disconnected, so here we have the potential difference between the plates to be given by the formula;
ΔV = Q/C
Now, the charge is conserved on the plates and the capacitance is constant, therefore in this case, the potential difference will remain the same.
Thus;
Potential Difference = 14 V