1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
shtirl [24]
3 years ago
11

A student visits the beach and wants to explore how landforms, such as sand dunes, are the result of changes caused by wind. wha

t is the best tool to use while observing these changes?
A Graduated cylinder
B Hand lens
C Camera
D Microscope
Physics
2 answers:
ella [17]3 years ago
7 0
Camera because it would be helpful to photograph the dunes at different times and compare the differences resulting from wind.
posledela3 years ago
3 0
C Camera. I think this because you can make timelapses with cameras which makes it easy to see.
You might be interested in
What is latent heat? Group of answer choices Energy released when water evaporates. Energy hidden in water vapor in the air. Ene
Andrews [41]

Answer:

Energy absorbed or hidden when water evaporates

Explanation:

The heat that is required to make a phase change is known as latent heat.

A phase change occurs when matter changes state. For example from solid to liquid, from liquid to gas, among others.

When changing from liquid to gas (for example when water evaporates), the heat necessary for this to happen is called latent heat of vaporization. The word latent means hidden, because a change in temperature is not perceived during the phase change, even when heat is being added, thus it is said that the heat is hidden or latent.

So the answer is:

  • Energy absorbed or hidden when water evaporates.

*Another type of latent heat is the latent heat of fusion, which is when a solid becomes liquid.

7 0
3 years ago
The wheel of a stationary exercise bicycle at your gym makes one rotation in 0.670 s. Consider two points on this wheel: Point P
lesya [120]

Answer:

a) For P: v=0.938\frac{m}{s}

For Q: v = 1.876\frac{m}{s}

b) For P:

a_{rad}=8.80\frac{m}{s^{2}}

for Q:

a_{rad}=17.60\frac{m}{s^{2}}

c) As the distance from the axis increases then speed increases too.

Explanation:

a) Assuming constant angular acceleration we can find the angular speed of the wheel dividing the angular displacement θ between time of rotation:

\omega =\frac{\theta}{t}

One rotation is 360 degrees or 2π radians, so θ=2π

\omega =\frac{2\pi}{0.670} =9.38\frac{rad}{s}

Angular acceleration is at every point on the wheel, but speed (tangential speed) is different and depends on the position (R) respect the rotation axis, the equation that relates angular speed and speed is:

v = \omega R

for P:

v = 9.38\frac{rad}{s}*0.1m=0.938\frac{m}{s}

for Q:

v = 9.38\frac{rad}{s}*0.2m=1.876\frac{m}{s}

b) Centripetal acceleration is:

a_{rad}= \frac{v^2}{R}

for P:

a_{rad}= \frac{(0.938)^2}{0.1}=8.80\frac{m}{s^{2}}

for Q:

a_{rad}= \frac{(1.876)^2}{0.2}=17.60\frac{m}{s^{2}}

c) As seen on a) speed and distance from axis is v = \omega R because ω is constant the if R increases then v increases too.

3 0
3 years ago
In your own words, what was the purpose of the field study?
DanielleElmas [232]

Answer:

Hi there! I have only the procedure and the scientific names of the creatures. Hope this helps!

Procedure

I studied the physical features of ten creatures and classified them using the key. I completed each section below and recorded the creature's scientific name in the data section.

The Creatures Scientific Names:

1  

Fuzzus tallywag

2  

Fuzzus pointilus

3  

Silkus duosquirmus

4  

Fuzzus chompilus

5  

Silkus stretchilus

6  

Silkus tallyhas

7  

Fuzzus feelzalot

8  

Silkus monosquirmus

9  

Fuzzus squarilus

10  

Silkus monowrestle

Have a thrilling Thursday!

~Lola

6 0
3 years ago
A thin spherical shell with radius R1 = 4.00 cm is concentric with a larger thin spherical shell with radius R2 = 6.00 cm . Both
kakasveta [241]

Answer:

The right response will be "450 volts".

Explanation:

The given values are:

R1 = 4.00 cm

R2 = 6.00 cm

q1 = +6.00 nC

q2 = −9.00 nC

As we know,

The potential difference between the two shell's difference will be:

⇒  \Delta V=K[(\frac{q1}{R1}+\frac{q2}{R2})-(\frac{q1}{R1} +(\frac{q2}{R2}))]

           =K[\frac{q1}{R2}-\frac{q1}{R1} ]

On substituting the values, we get

           =(9\times 10^9)[\frac{6\times 10^{-9}}{0.04}-\frac{6\times 10^{-9}}{0.06}]  

       Δ =450 \ volts

3 0
3 years ago
Please help im being timed on this and need to get my grade up
nadya68 [22]

Answer:

a I think hope this helps

8 0
2 years ago
Other questions:
  • A string is wrapped several times around the rim of a small hoop with radius 8.00 cm and mass 0.180 kg. The free end of the stri
    12·2 answers
  • According to Charles's Law, if the pressure of a gas stays constant, when the temperature increases, the volume __________.
    15·2 answers
  • A bug is on the rim of a disk of diameter 9 in that moves from rest to an angular speed of 76 rev/min in 6.5 s. what is the tang
    8·1 answer
  • There are two pendulums with periods 1.5 s and 1 s, which one is longer, and which one is shorter.
    8·1 answer
  • If you double the net force on an object what is the result of the acceleration
    11·1 answer
  • PLZZ I WILL DO ANY THING
    13·1 answer
  • starting from rest , a formula one car accelerates uniformly at 25m\s2 for 30secs. what distance does it cover in the last one s
    7·1 answer
  • A system can only achieve a lower energy state by:_______
    12·1 answer
  • Two resistors R1 = 3 Ω and R2 = 6 Ω are connected in parallel. What is the net resistance in the circuit?​
    13·1 answer
  • How many milliliters are in 1 liter?
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!