Question

If f(x)=-x^2+6x-1 and g(x) =3x^2-4x-1, find (f-g)(x)

Answer 1

Answer:

Step-by-step explanation:

Given,

$f(x)=-x^{2} +6x-1\\g(x)=3x^{2} -4x-1$

we know,

(f-g)(x)=f(x)-g(x)

So, here we get

(f-g)(x)

=f(x)-g(x)

=$-x^{2} +6x-1-(3x^{2} -4x-1)$

=$-x^{2} +6x-1-3x^{2} +4x+1$

=$-x^{2}-3x^{2} +6x+4x-1+1$

=$-4x^{2} +10x$

So, the answer is

$-4x^{2} +10x$

Answer 2

Answer:

(f-g)(x) = -4x^2 + 10x - 2

Step-by-step explanation:

Writing f(x) first and then writing g(x) beneath it may make this problem a bit easier to understand:

 f(x)=    -x^2+6x -1

-g(x) = -3x^2+4x -1

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(f-g)(x) = -4x^2 + 10x - 2