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Llana [10]
3 years ago
10

If f(x)=-x^2+6x-1 and g(x) =3x^2-4x-1, find (f-g)(x)

Mathematics
2 answers:
asambeis [7]3 years ago
8 0

Answer:


Step-by-step explanation:

Given,

f(x)=-x^{2} +6x-1\\g(x)=3x^{2} -4x-1

we know,

(f-g)(x)=f(x)-g(x)

So, here we get

(f-g)(x)

=f(x)-g(x)

=-x^{2} +6x-1-(3x^{2} -4x-1)

=-x^{2} +6x-1-3x^{2} +4x+1

=-x^{2}-3x^{2} +6x+4x-1+1

=-4x^{2} +10x

So, the answer is

-4x^{2} +10x

Oksanka [162]3 years ago
8 0

Answer:

(f-g)(x) = -4x^2 + 10x - 2

Step-by-step explanation:

Writing f(x) first and then writing g(x) beneath it may make this problem a bit easier to understand:

 f(x)=    -x^2+6x -1

-g(x) = -3x^2+4x -1

-----------------------------

(f-g)(x) = -4x^2 + 10x - 2

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dusya [7]

Answer:

15

Step-by-step explanation:

half of 30 is 15

he used all the numbers upto 30 once

all the numbers in between arent integers but decimals

8 0
3 years ago
The largest possible circle is cut out of a square whose side length is 8 feet. What will be the approximate area, in square fee
Lunna [17]

Answer:

=13.73 ft²

Step-by-step explanation:

The diameter of the largest possible circle that can be cut out of  a square is equal to the length of the side of the square.

Therefore the diameter of the circle cut from a square of side 8ft =8ft

r=4ft

Area of the remaining board= Area of square- area of circle

=side²-πr²

=8²-π×4²

=64-16π

=13.73 ft²

6 0
3 years ago
7(z+2)-3z=44 quiero que me ayuden a resolver este problema por favor
slega [8]
No hablo expanol

7(z+2)-3z=44
7z+14-3z=44
7z-3z+14=44
4z+14=44
-14        -14
4z+14-14=44-14
4z+0=30
4z=30
1/4  1/4
(4z)/4=30/4
(4/4)z=15/2
1z=15/2
z=15/2



z=15/2
5 0
3 years ago
What is 6 3/4 x 3/5<br><br> A) 54/20<br><br> B) 75/12<br><br> C) 81/20<br><br> D) 9/4
steposvetlana [31]
The answer you are looking for is C my friend
8 0
3 years ago
Choose the answer that validates that the rate of change is constant by showing that the ratios of the two quantities are propor
docker41 [41]

Given:

The table of values is

Number of Students   :  7    14   21    28

Number of Textbooks : 35  70  105  140

To find:

The rate of change and showing that the ratios of the two quantities are proportional and equivalent to the unit rate.

Solution:

The ratio of number of textbooks to number of students are

\dfrac{35}{7}=5

\dfrac{70}{14}=5

\dfrac{105}{21}=5

\dfrac{140}{28}=5

All the ratios of the two quantities are proportional and equivalent to the unit rate.

Let y be the number of textbooks and x be the number of students, then

\dfrac{y}{x}=k

Here, k=5.

\dfrac{y}{x}=5

y=5x

Hence the rate of change is constant that is 5.

8 0
3 years ago
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