Ask question

Ask question

All categories

PilotLPTM [1.2K]

3 years ago

9

Plz help me with this sum, see the pic. Thank you

1 answer:

lozanna [386]3 years ago

6 0

Answer:

${5}^{8} {x}^{6}$

Step-by-step explanation:

$\bigg( \frac{125 {x}^{ - 3} }{ {5}^{ - 3} \times 25 \times {x}^{ - 6} } \bigg)^{2} \\ \\ = \bigg( \frac{ {5}^{3} {x}^{ - 3} }{ {5}^{ - 3} \times {5}^{2} \times {x}^{ - 6} } \bigg)^{2} \\ \\ = {( {5}^{3 + 3 - 2} {x}^{ - 3 + 6} })^{2} \\ = {( {5}^{6 - 2} {x}^{3} )}^{2} \\ = {( {5}^{4} {x}^{3}) }^{2} \\ = {5}^{4 \times 2} {x}^{3 \times 2} \\ = {5}^{8} {x}^{6} \\$

You might be interested in

Is anyone able to figure this out, I can't do this

katrin [286]

Answer:

C. √2 - 1

Step-by-step explanation:

If we draw a square from the center of the large circle to the center of one of the small circles, we can see that the sides of the square are equal to the radius of the small circle (see attached diagram)

Let r = the radius of the small circle

Using Pythagoras' Theorem $a^2+b^2=c^2$

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

to find the diagonal of the square:

$\implies r^2 + r^2 = c^2$

$\implies 2r^2 = c^2$

$\implies c=\sqrt{2r^2}$

So the diagonal of the square = $\sqrt{2r^2}$

We are told that the radius of the large circle is 1:

⇒ Diagonal of square + r = 1

$\implies \sqrt{2r^2}+r=1$

$\implies \sqrt{2r^2}=1-r$

$\implies 2r^2=(1-r)^2$

$\implies 2r^2=1-2r+r^2$

$\implies r^2+2r-1=0$

Using the quadratic formula to calculate r:

$\implies r=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\implies r=\dfrac{-2\pm\sqrt{2^2-4(1)(-1)}}{2(1)}$

$\implies r=\dfrac{-2\pm\sqrt{8}}{2}$

$\implies r=-1\pm\sqrt{2}$

As distance is positive, $r=-1+\sqrt{2}=\sqrt{2}-1$ only

5 0

2 years ago

Read 2 more answers

Thanks for help have nice day

kupik [55]

Answer: 6. d

7. b

8. d

9. c

Step-by-step explanation:

8 0

2 years ago

Justin completed 85% of a book when he read the first 170 pages. How many pages are in the book?

ICE Princess25 [194]

There are 200 pages

6 0

2 years ago

Read 2 more answers

Please help will vote brainliest. Due soon please

egoroff_w [7]

They are similars because If you see the picture

7 0

3 years ago

Line j passes through points 1,6 and 7,1 line k is parallel to line j. What is the slope of line k?

Mashutka [201]

Slope formula m = (y2-y1) / (x2 - x1)
m = (1 - 6) / 7 - 1)
m = -5 / 6

Slope or parallel lines are the same
Slope = -5/6

6 0

2 years ago