(a) The time for the capacitor to loose half its charge is 2.2 ms.
(b) The time for the capacitor to loose half its energy is 1.59 ms.
<h3>
Time taken to loose half of its charge</h3>
q(t) = q₀e-^(t/RC)
q(t)/q₀ = e-^(t/RC)
0.5q₀/q₀ = e-^(t/RC)
0.5 = e-^(t/RC)
1/2 = e-^(t/RC)
t/RC = ln(2)
t = RC x ln(2)
t = (12 x 10⁻⁶ x 265) x ln(2)
t = 2.2 x 10⁻³ s
t = 2.2 ms
<h3>
Time taken to loose half of its stored energy</h3>
U(t) = Ue-^(t/RC)
U = ¹/₂Q²/C
(Ue-^(t/RC))²/2C = Q₀²/2Ce
e^(2t/RC) = e
2t/RC = 1
t = RC/2
t = (265 x 12 x 10⁻⁶)/2
t = 1.59 x 10⁻³ s
t = 1.59 ms
Thus, the time for the capacitor to loose half its charge is 2.2 ms and the time for the capacitor to loose half its energy is 1.59 ms.
Learn more about energy stored in capacitor here: brainly.com/question/14811408
#SPJ1
Answer:
what is the question I cannot click the
Explanation:
Answer:
36.74 N
Explanation:
Given that:
A crate of oranges with a total mass (m) = 6.7 kg
angle θ = 0.7 rad
angle θ = 
angle θ = 40°
acceleration = 4.2 m/s²
Given that:
T cosθ = ma
T cos 40° = 6.7 × 4.2
T = 
T = 
T = 36.74 N
Thus, the tension in the rope = 36.74 N
Answer:
<h3>i think it is 7.10 </h3>
Explanation:
I dont have an explenation
Explanation:
o has Celsius of indirect measurment
