F = 2820.1 N
Explanation:
Let the (+)x-axis be up along the slope. The component of the weight of the crate along the slope is -mgsin15° (pointing down the slope). The force that keeps the crate from sliding is F. Therefore, we can write Newton's 2nd law along the x-axis as
Fnet = ma = 0 (a = 0 no sliding)
= F - mgsin15°
= 0
or
F = mgsin15°
= (120 kg)(9.8 m/s^2)sin15°
= 2820.1 N
Answer:
36 km/h
Explanation:
The total velocity is the sum of the two velocities that add to the movement of the boat.
Since the wind pushes the boat at 21 km/h and the current that runs in the direction of the movent of the boat is 15 km/h, the total velocity at wich the boat moves is:
21km/h + 15 km/h = 36 km/h
Normal force, weight, Kinetic friction, and air resistance are a few I think of the top of my head.
I hope this helps
<h2>Answer</h2>
Radius is 421 m.
<u>Explanation </u>
A car with a mass of 1,500 kg requires a centripetal force of 640 N to safely follow a circular curve in the road at 13.4 m/s. Therefore, for radius we use formula which is Fc = mv ^ 2 / r,
As mass = m = 1500kg,
Centripetal force = Fc = 640N,
Velocity = v = 13.4 m / s
By putting values, Fc = mv ^ 2 / r,
r = mv ^ 2 / Fc,
=> r = ( 1500kg ) . ( 13.4 m / s) ^ 2 / 640,
=> r = ( 1500kg ) . ( 179.56 ) / 640,
r = 269340 / 640,
=> r = 420.84 m.
Radius is 421 m.
Pulling a dogs leash: inertia
