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andrezito [222]
3 years ago
12

William's typical running speed is 6 mi/h. The difference between his fastest speed and his typical speed is 1.5 min. The equati

o
f-1.5 = 6 can be used to represent this problem, where fis William's fastest speed. What is William's fastest speed?

A) 4.5 mi/h
B) 5.5 mi/h
C)6.5mi/h
D) 7.5 mi/h
Mathematics
2 answers:
Over [174]3 years ago
6 0

Answer:

D) 7.5 mi/h. hcbhcvu yc yv. y yv yh

ladessa [460]3 years ago
5 0

Answer:

D

Step-by-step explanation:

7.5

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The equation has one extraneous solution which is n ≈ 2.38450287.

Given that,

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According to the question,

An extraneous solution is a solution value of the variable in the equations, that is found by solving the given equation algebraically but it is not a solution of the given equation.

To solve the equation cross multiplication process is applied following all the steps given below.

\rm \dfrac{9}{n^2+1} =\dfrac{n+3}{4}\\\\9 (4) = (n+3) (n^2+1)\\\\36 = n(n^2+1) + 3 (n^2+1)\\\\36 = n^3+ n + 3n^2+3\\\\n^3+ n + 3n^2+3 - 36=0\\\\n^3+ 3n^2+n -33=0\\

The roots (zeros) are the  x  values where the graph intersects the x-axis. To find the roots (zeros), replace  y

with  0  and solve for  x. The graph of the equation is attached.

n  ≈  2.38450287

Hence, The equation has one extraneous solution which is n  ≈  2.38450287

For more information refer to the link.

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5 0
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