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vredina [299]
3 years ago
6

Easy question for points 1/3 in decimal form ps I know the answer

Mathematics
2 answers:
valina [46]3 years ago
7 0

Answer:

0.3333 (the three continues)

Step-by-step explanation:

If you put 1/3 or 1 divided by 3 in the calculator, then it'll show the decimal form of the fraction.

Akimi4 [234]3 years ago
4 0

Answer:

0.333

Step-by-step explanation:

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Out of 195 students, 9% have
mart [117]

Answer:

round it to 18 since 9% of 195 is 17.55

Step-by-step explanation:

6 0
3 years ago
Jackie and a classmate spent a total of 20 hrs working on a chemistry project. Jackie’s classmate spent 2 hrs less time working
valina [46]

Answer:

x = 11

Step-by-step explanation:

x + (x - 2) = 20

2x - 2 = 20

2x - 2 + 2 = 22 + 2

2x = 22

x = 11

7 0
3 years ago
Please help, and thank you!
lawyer [7]

Answer:

3. C

4. D

Step-by-step explanation:

3.

x^2+25=0\\x^2=-25\\x=\pm\sqrt{-25}

Once \sqrt{-1}=i

x=\pm5i

4.

A quadratic equation has no real roots when the discriminant (\Delta) is negative. \Delta.

Let's try all the equations:

(A)

2x^2-7x-9=0\\\\\Delta=\sqrt{\left(-7\right)^2-4\cdot \:2\left(-9\right)}\\\Delta=\sqrt{\left(-7\right)^2+4\cdot \:2\cdot \:9}\\\Delta=\sqrt{121} \\\Delta=11

(B)

2x^2=7x\\2x^2-7x=0\\x(2x-7)=0\\x=0\\\text{or}\\2x-7=0\\2x=7\\\\

$x=\frac{7}{2} $

(C)

2x^2+7x-9=0\\\Delta = \sqrt{7^2-4\cdot \:2\left(-9\right)}\\\Delta = \sqrt{7^2+4\cdot \:2\cdot \:9}\\\Delta = \sqrt{121} \\\Delta= 11

(D)

2x^2-7x+9=0\\\Delta = \sqrt{\left(-7\right)^2-4\cdot \:2\cdot \:9}\\\\\Delta=\sqrt{-23} \\\Delta=\sqrt{23i}

8 0
3 years ago
Can anyone help me to understand how to solve coordinate proofs in Geometry?????
nataly862011 [7]

The coordinate proof is a proof of a geometric theorem which uses "generalized" points on the Cartesian Plane to make an argument.The method usually involves assigning variables to the coordinates of one or more points, and then using these variables in the midpoint or distance formulas .For example, the following is a coordinate proof of the Triangle Midsegment Theorem , which states that the segment connecting the midpoints of two sides of a triangle is parallel to the third side and exactly half the length.Without loss of generality, we can assume that one side of the triangle lies on the xx -axis with one vertex at (0,0)(0,0) and the other vertex at(a,0)(a,0).Let the third vertex have the coordinates (b,c)(b,c) . We can assume without loss of generality that this third vertex lies in the first quadrant. (If it doesn't, you can just reflect the triangle over the xx - and/or yy -axis until it does.)

Example:

To Prove: XY¯¯¯¯¯¯XY¯ is parallel to PR¯¯¯¯¯PR¯ and

<span><span>XY=<span>12</span>PR</span><span>XY=<span>12</span>PR</span></span>

Proof:

Using the midpoint formula , the coordinates of the midpoints XX and YY are

<span><span><span>X<span>(<span><span><span>0+b</span>2</span>,<span><span>0+c</span>2</span></span>)</span>=X<span>(<span><span>b2</span>,<span>c2</span></span>)</span></span><span>Y<span>(<span><span><span>a+b</span>2</span>,<span><span>0+c</span>2</span></span>)</span>=Y<span>(<span><span><span>a+b</span>2</span>,<span>c2</span></span>)</span></span></span><span><span>X<span>(<span><span><span>0+b</span>2</span>,<span><span>0+c</span>2</span></span>)</span>=X<span>(<span><span>b2</span>,<span>c2</span></span>)</span></span><span>Y<span>(<span><span><span>a+b</span>2</span>,<span><span>0+c</span>2</span></span>)</span>=Y<span>(<span><span><span>a+b</span>2</span>,<span>c2</span></span>)</span></span></span></span>

First note that the <span>slope </span>is <span>00</span> , since

<span><span><span>m=<span>riserun</span></span><span>     =<span><span>(<span><span>c2</span>−<span>c2</span></span>)</span><span>(<span><span>b2</span>−<span>(<span><span>a+b</span>2</span>)</span></span>)</span></span></span><span>     =<span>0<span>(<span><span>b2</span>−<span>(<span><span>a+b</span>2</span>)</span></span>)</span></span></span><span>     =0</span></span><span><span>m=<span>riserun</span></span><span>     =<span><span>(<span><span>c2</span>−<span>c2</span></span>)</span><span>(<span><span>b2</span>−<span>(<span><span>a+b</span>2</span>)</span></span>)</span></span></span><span>     =<span>0<span>(<span><span>b2</span>−<span>(<span><span>a+b</span>2</span>)</span></span>)</span></span></span><span>     =0</span></span></span>

So, <span><span><span>XY</span><span>¯¯¯¯¯¯</span></span><span><span>XY</span>¯</span></span> is parallel to <span><span><span>PR</span><span>¯¯¯¯¯</span></span><span><span>PR</span>¯</span></span> .

Now, compare the lengths of the two segments.

<span><span><span>XY=<span><span>a+b</span>2</span>−<span>b2</span></span><span>        =<span>a2</span></span><span>PR=a−0</span><span>        =a</span></span><span><span>XY=<span><span>a+b</span>2</span>−<span>b2</span></span><span>        =<span>a2</span></span><span>PR=a−0</span><span>        =a</span></span></span>

So,

<span><span>XY=<span>12</span>PR</span><span>XY=<span>12</span>PR</span></span>

Thanks to google for example


hope this helps

8 0
3 years ago
The equation of line q is y = 1/3x-7Parallel to line q is liner, which passes through the
grigory [225]

Answer:

y =  \frac{1}{3} x - 10

Step-by-step explanation:

The equation of a line is usually written in the form of y=mx+c, where m is the gradient and c is the y-intercept.

Parallel lines have the same gradient. Hence the gradient of line r is \frac{1}{3}.

Susbt. m=\frac{1}{3},

y =  \frac{1}{3} x + c

To find c, substitute a coordinate.

When x=3, y= -9,

- 9 =  \frac{1}{3} (3) + c

-9= 1 +c

c= -9-1

c= -10

Thus the equation of line r is y =  \frac{1}{3} x - 10.

7 0
3 years ago
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