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vitfil [10]
4 years ago
15

How do I graph this two line equation.

Mathematics
1 answer:
Kamila [148]4 years ago
4 0
Equation 1 on your graph plot point 2 on your horizontal line. Then go UP 1 and to the RIGHT 3. Equation 2 use zero as your x intercept then go UP 1 and to the RIGHT 3. Good luck!
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guse lagrange multipliers to find the maximum or minimum values of the function subject to the given constraint. (if an answer d
Novosadov [1.4K]

Therefore the maximum value of function f(x,y,z)=x^{2} y^{2} z^{2} =1/27

And the minimum value is 0

<h3>What is function?</h3>

function, in mathematics, an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable) (the dependent variable) (the dependent variable) (the dependent variable). Mathematics uses functions frequently, and functions are essential for specifying physical relationships in the sciences.

Here,

The function is given as:

f(x,y,z)=x^{2} y^{2} z^{2}

x^{2} +y^{2}+ z^{2}=1

=>x^{2} +y^{2}+ z^{2}-1=0

Using Lagrange multiplies, we have:

L(x,y,z,λ)=f(x,y,z) +λ(0)

Substitute f(x,y,z)=x^{2} y^{2} z^{2}  and x^{2} +y^{2}+ z^{2}-1=0

Differentiate

L(x)=2xy^{2} z^{2}+2λx

L(y)=2yx^{2} z^{2}+2λy

L(z)=2zx^{2} y^{2}+2λz

L(λ)=x^{2} +y^{2}+ z^{2}-1

Equating to 0

2xy^{2} z^{2}+2λx =0

2yx^{2} z^{2}+2λy = 0

2zx^{2} y^{2}+2λz = 0

x^{2} +y^{2}+ z^{2}-1 = 0

Factorize the above expressions

2xy^{2} z^{2}+2λx =0

2x(y^{2} z^{2}+λ)=0

2x=0 and (y^{2} z^{2}+λ)=0

x=0 and  y^{2} z^{2}= -λ

2yx^{2} z^{2}+2λy = 0

2y(x^{2} z^{2}+λ)=0

2y=0 and (x^{2} z^{2}+λ)=0

y=0 and  x^{2} z^{2}= -λ

2zx^{2} y^{2}+2λz = 0

2z(y^{2} x^{2}+λ)=0

2z=0 and (x^{2} y^{2}+λ)=0

z=0 and  x^{2} y^{2}= -λ

So we have ,

x=0 and  y^{2} z^{2}= -λ

y=0 and  x^{2} z^{2}= -λ

z=0 and  x^{2} y^{2}= -λ

The above expression becomes

x=y=z=0

This means that,

x^{2} +y^{2}+ z^{2}=1

x^{2} +x^{2}+ x^{2} =1 \\3x^{2 } =1

x= ±1/\sqrt{3}

So,

y= ±1/\sqrt{3}

z= ±1/\sqrt{3}

The critic points are

x=y=z=±1/\sqrt{3}

x=y=z=0

Therefore the maximum value of function f(x,y,z)=x^{2} y^{2} z^{2} =1/27

And the minimum value is 0

To know  more about function , visit

brainly.com/question/12426369

#SPJ4

3 0
1 year ago
A circle is drawn within a square as shown.
Zinaida [17]
Answer is 86.47 cm hope helped
4 0
3 years ago
Find the center and radius of (x-4)2 + (y+2)2 = 32
Trava [24]

Step-by-step explanation:

General equation of the circle with center (h,k) and radius r,

(x-h)²+(y-k)²=r²

Therefore, on comparison

center ( 4, -2)

radius r= 4√2

6 0
3 years ago
Will give brainiest Will give brainiest Will give brainiest Will give brainiest Will give brainiest Will give brainiest Will giv
Licemer1 [7]

Answer:

222.7 cm³ of paper to wrap this.

Step-by-step explanation:

The rectangular prism is SA=2(wl+hl+hw)

Where:

w=5  l=5 h=4  

SA= 2((5*5)+(4*5)+(4*5))

SA=2(25+20+20)

SA=2(65)=130cm³

The square base pyramid is A= lw+l\sqrt{x} (w/2)^2+h^2+w +w\sqrt{x} (1/w)^2+h^2

SA= 6*5+6*\sqrt{x} (5/2)^2+5^2+5*\sqrt{x} (6/2)^2

≈92.69578 cm³

Add the two together 130+92.70 =222.7 cm³

5 0
4 years ago
Read 2 more answers
A car dealership sold the following colors of cars in January.
sweet [91]
The answer is A. 28%
7 0
3 years ago
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