The slope is 180 since that’s on the y-int.
1.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-2);y=-x-2
D.y=-x
2.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (2,-1);y=-3/2x-6
C.y=-3/2x+2
3.Write an equation in slope- intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (4,2);x=-3
D.y=4
4.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-2,3);y=1/2x-1
B.y=-2x-1
5.Write an equation in slope- intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (5,0);y+1=2(x-3)
D.y=-1/2x+5/2
Answer:
(−2)×5<(−20)
Step-by-step explanation:
Evaluating the options given :
(−2)×5<(−20)
Open the bracket
- 10 < - 20 (false) ` This expression isn't true
(−2)×(−5)>(−25)
Open the bracket
10 > - 25 (true)
2×5>(−25)
Open the bracket
10 > - 25 (true)
2×(−5)<20
Open the bracket
- 10 < 20
Answer:
The slope is 2
Step-by-step explanation:
Formula: y2-y1/x2-x1= 11-5/7-4 = 6/3=2
