All categories

3 years ago

According to the Arrhenius equation, changing which factors will affect the

Chemistry

1 answer:

slamgirl [31]3 years ago

6 0

Answer:

e−(Ea/RT): the fraction of the molecules present in a gas which have energies equal to or in excess of activation energy at a particular temperature

You might be interested in

How does delta g affect keq?

Iteru [2.4K]

The change in Gibbs Free Energy for any reaction is related to the equilibrium constant by the simple equation- thats all i know

6 0

3 years ago

If the reaction N2 (g) + 3 H2 (g) --> 2 NH3 (g) has the concentrations 1.1 M for nitrogen, 0.75 M for hydrogen and 0.25 M fo

Luba_88 [7]

Answer: The value of $K_c$ is 0.136 and is reactant favored.

Explanation:

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{c}$

For the chemical reaction between carbon monoxide and hydrogen follows the equation:

$N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)$

The expression for the $K_{c}$ is given as:

$K_{c}=\frac{[NH_3]^2}{[N_2][H_2]^3}$

We are given:

$[NH_3]=0.25M$

$[H_2]=0.75M$

$[N_2]=1.1M$

Putting values in above equation, we get:

$K_c=\frac{(0.25)^2}{1.1\times (0.75)^3}$

$K_c=0.135$

There are 3 conditions:

When $K_{c}>1$ ; the reaction is product favored.
When $K_{c}$ ; the reaction is reactant favored.
When $K_{c}=1$ ; the reaction is in equilibrium.

For the given reaction, the value of $K_c$ is less than 1. Thus, the reaction is reactant favored.

Hence, the value of $K_c$ is 0.136 and is reactant favored.

4 0

3 years ago

Four satellites orbit Earth at similar distances.Which object experiences the smallest gravitational force with Earth?

guapka [62]

Answer:

Explanation: the satellite with the smallest mass

3 0

2 years ago

The pH of 0.50 M benzoic acid is 2.24. Calculate the change in pH when 2.64 g of C6H5COONa is added to 38 mL of 0.50 M benzoic a

meriva

Answer:

1.93

Explanation:

Moles of C $_{6}$ H $_{5}$ COOH = 38/1000 × 0.50 = 0.019mol

Moles of C $_{6}$ H $_{5}$ COONa = Mass/Molar mass = 2.64/144.10 = 0.018321mol

Final pH = pKa + log([C $_{6}$ H $_{5}$ COONa]/[C $_{6}$ H $_{5}$ COOH]

= -log Ka + log(mols of C $_{6}$ H $_{5}$ COONa]/mols of C $_{6}$ H $_{5}$ COOH

= -log(6.5 × 10^(-5)) + log (0.018321/0.019)=4.17

change in pH = final - initial pH

= 4.17 - 2.24

=1.93

5 0

4 years ago

Convert 220 grams of CO2 into Moles.

LenaWriter [7]

Answer:

. 44.0 g/mol.

Explanation:

4 0

3 years ago

Read 2 more answers