Answer:
Option A is correct. A tertiary amine will not form an amide with acyl chlorides they can only transform acyl chlorides into ketenes.
Explanation:
(a). Reaction of acyl chloride with aniline: Aniline is the simplest primary amine. The -NH2 group is attached directly to the benzene ring. The equation of reaction is given below;
CH3COCl + 2C6H5NH2----------> CH3CONHC6H5 +C6H5NH3Cl.
The products of the reaction are The products are N-phenylethanamide,C6H5NH2 and phenylammonium chloride, C6H5NHCl.
(b). Reaction of acyl chloride with primary and secondary amine:
The -NH2 is attached to an alkyl group for the primary and secondary amine. Typical reaction equation for a primary amine with acyl chloride is given below;
CH3COCl + CH3NH2------------------> CH3CONHCH3 + HCl.
The HCl will further react with NH3 to produce The salt is called methylammonium chloride.
(c). Reaction of acyl chloride with amine: the equation of reaction is given below;
CH3COCl + NH3 --------------> CH3CONH2 + HCl.
The hydrogen chloride produced reacts with excess ammonia to form ammonium chloride;
NH3 + HCl ---------------> NH4Cl.
It think it has exactly 9
In order for us to help we need more information. Possibly the amount of grams you used for Mg in trial 1 or something similar to this.
Answer:
b. 295 pm
Explanation:
To answer this question we need to use the equation of a face-centered cubic laticce:
Edge length = √8 R
<em>Where R is radius of the atom.</em>
<em />
Replacing:
417pm = √8 R
R = 147.4pm is the radius of the atom
As diameter = 2 radius.
Diameter of the metal atom is:
147.4pm* 2 =
295pm
Right answer is:
<h3>b. 295 pm
</h3>
2 possibly 3 depends on if that of what looks like a zero is an O which it isn't so 2 but if it is 3.
