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Troyanec [42]
2 years ago
6

Number 14 please help.. chemistry

Chemistry
1 answer:
Zolol [24]2 years ago
7 0

Taking into account the definition of density, the mass of a substance with a volume of 150 cm³ and a density of 1.5 \frac{g}{cm^{3} }  is 225 grams.

<h3>What is density</h3>

Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.

Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density=\frac{mass}{volume}

From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

<h3>Mass of the substance in this case</h3>

In this case, you know that:

  • Density= 1.5 \frac{g}{cm^{3} }
  • Volume= 150 cm³

Replacing in the definition of density:

1.5 \frac{g}{cm^{3} } =\frac{mass}{150 cm^{3} }

Solving:

mass= 1.5 \frac{g}{cm^{3} }  ×150 cm³

<u><em>mass= 225 g</em></u>

In summary, the mass of a substance with a volume of 150 cm³ and a density of 1.5 \frac{g}{cm^{3} }  is 225 grams.

Learn more about density:

brainly.com/question/952755

brainly.com/question/1462554

#SPJ1

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jarptica [38.1K]

Answer:

F = 50 N

Explanation:

Given data:

Mass of car = 250 Kg

Acceleration of car = 0.20 m/s²

Force required = ?

Solution:

Formula:

F = m×a

F = applied  force

m = mass

a = acceleration

Now we will put the values in formula.

F =  250 Kg × 0.20 m/s²

F = 50 Kg.m/s²

Kg.m/s² = N

F = 50 N

3 0
2 years ago
What happens to the pressure if the gas volume is cut in half while n and I are<br> held constant?
N76 [4]

Answer: You can use Boyle's law, which states that pressure is inversely related to volume when other variables are held constant. If the final pressure of a gas is half of the initial, the volume must double if temperature is to remain the same.

Explanation:

5 0
3 years ago
How many milliliters of an aqueous solution of 0.170 M ammonium carbonate is needed to obtain 16.1 grams of the salt
Citrus2011 [14]

There will be needed 982.35 mL of solution to obtain 16.1 grams of the salt.There will be needed mL of

Why?

In order to calculate how many milliliters are needed to obtain 16.1 grams of the salt given its concentration, we first need to find its chemical formula which is the following:

(NH_{4})2CO_{3}

Now that we know the chemical formula of the substance, we need to find its molecular mass. We can do it by the following way:

N_{2}=14g*2=28g\\\\2H_{4}=2*1g*4=8g\\\\C=12.01g*1=12.01g\\\\O_{3}=15.99g*3=47.97g

We have that the molecular mass of the substance will be:

MolecularMass=\frac{28g+8g+12.01g+47.97g}{mol}=95.98\frac{g}{mol}

Therefore, knowing the molecular mass of the substance, we need to calculate how many mols represents 16.1 grams of the same substance, we can do it by the following way:

mol_{(NH_{4})2CO_{3}=\frac{mass_{(NH_{4})2CO_{3}}}{molarmass_{(NH_{4})2CO_{3}}}

mol_{(NH_{4})2CO_{3}=\frac{16.1g}{95.98\frac{g}{mol}}=0.167mol

Finally, if we need to calculate how many milliliters are needed, we need to use the following formula:

M=\frac{moles_{solute}}{volume_{solution}}

M=\frac{moles_{solute}}{volume_{solution}}\\\\volume_{solution}=\frac{moles_{solute}}{M}

Now, substituting and calculating, we have:

volume_{solution}=\frac{0.167mol}{0.170\frac{mol}{L}}\\\\volume_{solution}=0.982L=0.982L*1000=982.35mL

Henc, there will be needed 982.35 mL of solution to obtain 16.1 grams of the salt.

Have a nice day!

5 0
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Answer:

A solid material whose constituents (such as atoms, molecules, or ions) are arranged in a highly ordered microscopic structure, forming a crystal lattice that extends in all directions.

Explanation:

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Explanation:

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