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zzz [600]
3 years ago
9

Work the following pricing problems for services rendered. (Round to hundredths.) Hourly rate, worker A = $15.00 Hourly rate, wo

rker B = $8.00 Hourly rate, worker C = $5.25 Labor time, worker A = 2 1/2 hours Labor time, worker B = 1 hour Labor time, worker C = 3/4 hour Overhead rate = 75% Retail price of goods = $125.50 Total cost of job? 137.86 165.58 187.30 212.02
Mathematics
1 answer:
svlad2 [7]3 years ago
7 0
Hello there :-)

Total cost of job=retail price of goods+labor cost+overhead

Labor cost
15×2.5+8×1+5.25×(3÷4)
=49.44 this is labor cost

Overhead= labor cost×overhead rate
Overhead=49.44×0.75=37.08

Now find total cost of job
Total cost of job=125.50+49.44+37.08
=212.02....answer

Hope it helps
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What number is 15% of 80?<br> use percent proportions
vova2212 [387]
!5% is equivalent to 15 parts over the whole 100 part. It is written in proportions as 15/100. 

Similarly, you need to find how many parts in 80 are equivalent to 15%or 15/100. So, just equate both equation with x as an unknown.

x/80 = 15/100
x = (15/100)*80
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Thus, the 15% of 80 is 12.
8 0
2 years ago
HELP ASAP Use the data below
beks73 [17]

Answer:

Part A:

   -Minimum: 10

   -Q1: 17.5

   -Median: 30

   -Q3: 42.5

   -Maximum: 50

Step-by-step explanation:

Part B: IQR= 25

This shows that the data varies for 25 different numbers. That HALF of the data is between 25 numbers.

Part C: Using a box-and-whisker plot you can interpret the different values. Minimum is the first dot (10), connected to the first line (Q1 which is 17.5), connected by a box to the median (30), connected by a box to the third line (Q3 which is 42.5), connected to the last dot which is the maximum (50). And IQR is Q3-Q1, so 42.5-17.5 which is 25.

8 0
3 years ago
Using the technique in the model above, find the missing sides in this 30°-60°-90° right triangle.
ale4655 [162]
Umm..... according to what I know      <span> </span><span>The ratio of the sides of a 30°-60°-90° triangle are:
short leg : long leg : hypotenuse
1 : √3 : 2
</span><span> if the short leg is 7, the long leg is √3 times that:
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8 0
3 years ago
Read 2 more answers
Q 1 PLEASE HELP ME FIGURE THIS OUT 2
dimulka [17.4K]

Answer: \frac{\pi }{3}

<u>Step-by-step explanation:</u>

cot is \frac{cos}{sin} on the Unit Circle. When is cos = \frac{1}{2} and sin = \frac{\sqrt{3}} {2}?  In other words, where is the coordinate (\frac{1}{2},\frac{\sqrt{3}} {2}) on the Unit Circle?

It occurs at 60° = \frac{\pi }{3} radians

**************************************************************************************

Answer: cot θ

<u>Step-by-step explanation:</u>

  sec (90 - θ) * cos θ

= \frac{1}{cos (90 -\theta)} * cos θ

= \frac{cos\theta}{cos(90 - \theta)}

= \frac{cos\theta}{cos90*cos\theta+sin90*sin\theta}

= \frac{cos\theta}{0*cos\theta+1*sin\theta}

= \frac{cos\theta}{sin\theta}

= cot θ

**************************************************************************************

Answer: BC = √5, AC = 2√5

<u>Step-by-step explanation:</u>

\frac{\pi} {3} = 60°, which means ΔABC is a 30°-60°-90° triangle so we can use the side length formulas: x - x√3 - 2x.

∠C is the 60°. It matches to side AB so: AB = x√3 = √15   ⇒   x = √5

∠A is the 30°. It matches to side BC so: BC = x = √5

∠B is the 90°. It matches to side AC so: AC = 2x = 2(√5)  = 2√5

**************************************************************************************

Answer: k = 4, RS = 12, QS = 28

<u>Step-by-step explanation:</u>

\frac{QR}{MN} = \frac{RS}{NO}= \frac{QS}{MO}

\frac{24}{6} = \frac{RS}{3}= \frac{QS}{7}

proportionality constant k can be found with \frac{QR}{MN} = \frac{24}{6} = 4

\frac{QR}{MN} = \frac{RS}{NO}

→ 4 = \frac{RS}{3}

→ 4(3) = RS

→ 12 = RS

\frac{QR}{MN} = \frac{QS}{MO}

→ 4 = \frac{QS}{7}

→ 4(7) = QS

→ 28 = QS


3 0
3 years ago
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dimaraw [331]

Answer:

Okay, Tell em what ur trying to ask please :/- confused

Step-by-step explanation:

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