Answer:
For a function y = f(x), the range is the set of all the possible values of y.
In the question you wrote:
y = secx - 2
This can be interpreted as:
y = sec(x - 2)
or
y = sec(x) - 2
So let's see each case (these are kinda the same)
If the function is:
y = sec(x - 2)
Firs remember that:
sec(x) = 1/cos(x)
then we can rewrite:
y = 1/cos(x - 2)
notice that the function cos(x) has the range -1 ≤ y ≤ 1
Then for the two extremes we have:
y = 1/1 = 1
y = 1/-1 = -1
Notice that for:
y = 1/cos(x - 2)
y can never be in the range -1 < x < 1
As the denominator cant be larger, in absolute value, than 1.
Then we can conclude that the range is all reals except the interval:
-1 < y < 1
If instead the function was:
y = sec(x) - 2
y = 1/cos(x) - 2
Then with the same reasoning, the range will be the set of all real values except:
-1 - 2 < y < 1 - 2
-3 < y < -1
The width is 11m and the length is 23m
3. 12 a
4. 7b-10
all you have to do is add up all of the sides.
Answer:
y - 7 = 16/13(x - 7)
General Formulas and Concepts:
<u>Alg I</u>
Point-Slope Form: y - y₁ = m(x - x₁)
Slope Formula: 
Step-by-step explanation:
<u>Step 1: Define</u>
Point (-6, -9)
Point (7, 7)
<u>Step 2: Find slope </u><u><em>m</em></u>
- Substitute:

- Add:

<u>Step 3: Write equation</u>
y - 7 = 16/13(x - 7)
Answer: A
2x^2+2x-8 is the quotient when x+3 divides P(x)
=> P(x) = (2x² + 2x -8)(x + 3) = 2(x² + x - 4)(x + 3) = (x² + x - 4) (2x + 6)
=> the quotient when 2x+6 divides p(x) is x² + x - 4
Step-by-step explanation: