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fredd [130]
3 years ago
13

.Calculate the average rate of change of f(x) = 3x + 4 on the interval [2, 6]. Select any oth

Mathematics
1 answer:
makvit [3.9K]3 years ago
6 0

Answer:

Average rate of change= 3

Step-by-step explanation:

Recall the definition of average rate of change of a function f(x) in an interval [a,b]:

Average rate of change = \frac{f(b)-f(a)}{b-a}

In your case:

f(x) = 3x+4, and the interval  [a,b] i  [2,6], therefore:

Average rate of change = \frac{f(6)-f(2)}{6-2}=\frac{f(6)-f(2)}{4}

Now we evaluate the function at the two requested points:

f(x)=3x+4\\f(6)=3(6)+4=18+4=22\\f(2)=3(2)+4=6+4=10, then f(6)-f(2)=22-10=12

So finally the Average rate of change is: \frac{f(6)-f(2)}{6-2}=\frac{12}{4} =3

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The range of the function y=secx-2 is all reals except<br><br> -1 1 -3 -2
Umnica [9.8K]

Answer:

For a function y = f(x), the range is the set of all the possible values of y.

In the question you wrote:

y = secx - 2

This can be interpreted as:

y = sec(x - 2)

or

y = sec(x) - 2

So let's see each case (these are kinda the same)

If the function is:

y = sec(x - 2)

Firs remember that:

sec(x) = 1/cos(x)

then we can rewrite:

y = 1/cos(x - 2)

notice that the function cos(x) has the range -1 ≤ y ≤ 1

Then for the two extremes we have:

y = 1/1 = 1

y = 1/-1 = -1

Notice that for:

y = 1/cos(x - 2)

y can never be in the range  -1 < x < 1

As the denominator cant be larger, in absolute value, than 1.

Then we can conclude that the range is all reals except the interval:

-1 < y < 1

If instead the function was:

y = sec(x) - 2

y = 1/cos(x) - 2

Then with the same reasoning, the range will be the set of all real values except:

-1 - 2 < y < 1 - 2

-3 < y < -1

6 0
3 years ago
A rectangle is 12m longer than it is wide. Its perimeter is 68m. Find its length and width?
Juliette [100K]
The width is 11m and the length is 23m
5 0
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Help please))) please i need your help!!!)
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3. 12 a

4. 7b-10

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5 0
3 years ago
Read 2 more answers
Write the equation of the line that passes through the points (-6, -9) and
e-lub [12.9K]

Answer:

y - 7 = 16/13(x - 7)

General Formulas and Concepts:

<u>Alg I</u>

Point-Slope Form: y - y₁ = m(x - x₁)  

  • x₁ - x coordinate
  • y₁ - y coordinate
  • m - slope

Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (-6, -9)

Point (7, 7)

<u>Step 2: Find slope </u><u><em>m</em></u>

  1. Substitute:                   m=\frac{7+9}{7+6}
  2. Add:                             m=\frac{16}{13}

<u>Step 3: Write equation</u>

y - 7 = 16/13(x - 7)

3 0
3 years ago
If 2x^2+2x-8 is the quotient when x+3 divides P(x), which of th3 following is the quotient when 2x+6 divides p(x)?
maria [59]

Answer: A

2x^2+2x-8 is the quotient when x+3 divides P(x)

=> P(x) = (2x² + 2x -8)(x + 3) = 2(x² + x - 4)(x + 3) = (x² + x - 4) (2x + 6)

=> the quotient when 2x+6 divides p(x) is x² + x - 4

Step-by-step explanation:

7 0
2 years ago
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