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belka [17]
3 years ago
6

Fiona has $18 to spend. She spent $4.25, including tax, to buy a notebook. She needs to save $9.75, but she wants to buy a snack

. If crackers cost $0.50 per package including tax, what inequality would show the maximum number of pack
my, Dan, and Mike are competing in a cooking competition. They all used different amounts of milk from a container holding 6 gallons of milk.
Amy used 13% of the total milk in the container.
Dan used 0.14 of the total milk in the container.
Mike used 0.5 gallon of the total milk in the container.
Who used the greatest amount of milk from the container? Show your work and explain your answer in words.
Mathematics
2 answers:
Sati [7]3 years ago
4 0
18 - 4.25 = 13.75.
13.75 - 9.75 = what is left to spend, $4.00

This means she can buy no more than 8 cracker packs.

Katyanochek1 [597]3 years ago
4 0

Answer:

Part A:

Let the number of packs of crackers Fiona can buy be = x

In total Fiona has = $18

As per situation inequality forms:

4.25+9.75+0.5x \leq18

0.5x \leq4

x \leq8

So, Fiona can buy at most 8 packs of crackers.

Part B:

Total milk = 6 gallons

Amy used 13% of the total milk in the container.

This becomes: 0.13\times6=0.78 gallons.

Dan used 0.14 of the total milk in the container.

This becomes: 0.14\times6=0.84 gallons

Mike used 0.50 gallon of the total milk in the container.

Comparing all we get Dan used the greatest amount of milk from the container.

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3 years ago
Jim, Carla and Tomy are members of the same family. Carla is 5 years older than Jim. Tomy is 6 years older than Carla. The sum o
Blizzard [7]

We are given these three people age below:

  • Jim's age
  • Carla's age
  • Tomy's age

We define the age of Jim as any variable, because the problem doesn't give any specific age. I will define Jim's age as x.

  • Jim's age = x

Next, Carla is 5 years older than Jim. That means if Carla is 5 years older, her age would be x+5.

  • Carla's age = x+5

Then Tomy is 6 years older than Carla. That means the age would be 6+(x+5).

  • Tomy's age = 6+(x+5)

The sum of their three ages is 31 years old. That means we add all these ages and equal to 31.

\large{x + x + 5 + 6 + x + 5 = 31}

Combine like terms and solve for x.

\large{3x + 16 = 31}  \\  \large{3x = 31 - 16} \\  \large{3x = 15} \\  \large{x = 5}

Then we substitute the value of x in ages to find these three people ages.

  • Jim's age = x = 5
  • Carla's age = x+5 = 5+5 = 10
  • Tomy's age = 6+(x+5) = 6+(5+5) = 6+10 = 16.

Answer

  • Jim's age = 5
  • Carla's age = 10
  • Tomy's age = 16
4 0
3 years ago
If $x$ is the average of $13$, $-16$, and $6$ and if $y$ is the cube root of $8$, find $x^2 + y^3$. Please Help
Alekssandra [29.7K]

Answer:

If we have a set of N elements:

{x₁, x₂, ..., xₙ}

The mean value (also called the average value) Is calculated as:

Average = (x₁ + x₂ + ... + xₙ)/n

So if x is the average of 13, -16 and 6 ( a total of 3 values)

x will be equal to:

x = (13 + (-16) + 6)/3 = (19 - 16)/3 = 3/3 = 1

x = 1

And we know that:

y = ∛8

Remember that:

2*2 = 4

and

4*2 = 8

then

2*2*2 = 2^3 = 8

then ∛8 = 2.

So we have:

y = ∛8 = 2

Now we can replace these values in the equation:

x^2 + y^3

replacing:

x = 1

y = 2

we get:

1^2 + 2^3 = 1 + 8 = 9

5 0
3 years ago
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