2/9=2.50
Allowence=2.50x9 divided by which gives you an answer of 11.25
Hope this helps you!
Answer:
No.
Step-by-step explanation:
They are not because the left side is 52, while the right side is 0.
PEMDAS is an acronym that refers to the sequence of operations to be employed when solving equations with multiple operations. The solution of the given expression (2×2)² - [3+(2×2)]/(6-4) is 14.
<h3>What is PEMDAS?</h3>
PEMDAS is an acronym that refers to the sequence of operations to be employed when solving equations with multiple operations. PEMDAS is an acronym that stands for P-Parenthesis, E-Exponents, M-Multiplication, D-Division, A-Addition, and S-Subtraction.
As per the rule of PEMDAS, the given expression can be simplified as shown below.
(2×2)² - [3+(2×2)]/(6-4)
Step 1: Solving Parenthesis,
= 4² - (3+4) / (2)
= 4² - 4/2
Step 2: Solving exponents,
= 16 - 4/2
Step 3: Solving Divisions,
= 16 - 2
Step 4: Solving Subtraction,
= 14
Hence, the solution of the given expression (2×2)² - [3+(2×2)]/(6-4) is 14.
Learn more about PEMDAS here:
brainly.com/question/36185
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Answer: 14 miles ≤ D ≤ 22 miles.
Step-by-step explanation:
The mean distance traveled per gallon, is 18 miles.
But this can fluctuate, at most, by 4 miles.
Because we have here the "at most", we know that we should use the ≤, ≥ symbols.
Then, if the mean is 18mi, the range of possible distances traveled per gallon is:
(18 miles - 4 miles) ≤ D ≤ (18 miles + 4 miles)
Where D is the distance.
14 miles ≤ D ≤ 22 miles.
So the truck can get between 14 miles and 22 miles per gallon on the highway.
Answer:
P(A∣D) = 0.667
Step-by-step explanation:
We are given;
P(A) = 3P(B)
P(D|A) = 0.03
P(D|B) = 0.045
Now, we want to find P(A∣D) which is the posterior probability that a computer comes from factory A when given that it is defective.
Using Bayes' Rule and Law of Total Probability, we will get;
P(A∣D) = [P(A) * P(D|A)]/[(P(A) * P(D|A)) + (P(B) * P(D|B))]
Plugging in the relevant values, we have;
P(A∣D) = [3P(B) * 0.03]/[(3P(B) * 0.03) + (P(B) * 0.045)]
P(A∣D) = [P(B)/P(B)] [0.09]/[0.09 + 0.045]
P(B) will cancel out to give;
P(A∣D) = 0.09/0.135
P(A∣D) = 0.667