Question

What is the slope of line PQ?

Answer 1

Answer:

Step-by-step explanation:

Slope of a line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by the formula,

Slope = $\frac{y_2-y_1}{x_2-x_1}$

Slope of the line PQ passing through the two points P(-8, 2) and Q(4, 2) will be,

Slope '$m_1$' = $\frac{2-2}{-8-2}$ = 0

Therefore, slope of the line PQ parallel to the x-axis = 0

Slope of the line MN passing through the points M(8, 6) and N(8, -8) is,

Slope '$m_2$' = $\frac{6+8}{8-8}$ = ∞

Therefore, slope of the line MN parallel to y-axis is undefined.

Since, angle between the x-axis and y-axis is 90°,angle at the intersection  point between the lines parallel to x and y axis will be 90°.

These lines are perpendicular to each other.