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Novosadov [1.4K]
3 years ago
13

Use successive differences to classify the function

Mathematics
1 answer:
Mice21 [21]3 years ago
6 0
14 5 2 5 14 
<span>
-9 -3 3 9 </span>
<span>
.....6...6...6 </span>
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The answer is the last one (32x^7y^15)

You can bring x to the second power (x^2) because (x) is basically x^1. This is a basic exponent rule. (x^m)^n = x^m times n.

Then you can apply this rule to (2xy^3)^5. First you bring two to the fifth power and get 32. Then you bring x^5 according to the rule. Then you bring y^15, also because of the rule.

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