To solve this problem you must apply the proccedure shown below:
1. The problem asks for the area of a cross section that is parallel <span>to face ABCD. As is parallel to that face, you have can calculate its area as following:
A=12 cm x 6 cm
2. Therefore, the result is:
A=72 cm</span>²
The answer is: T<span>he area of a cross section that is parallel to face ABCD is 72 cm</span>².
Answer is <span>57.2π </span>
Answer: -1/8
Step-by-step explanation:
3/4 + -3/8 + -1/4
Find the LCM of 4, 8, and 4
That's 8 so you make an equivalent fraction for all fractions so the denominator is 8.
3/4 = 6/8
-3/8 = -3/8
-1/4 = -4/8
Now the expression looks like this:
6/8 + - 3/8 + -4/8
6/8 - 3/8 - 4/8
6/8 - 7/8
-1/8
Hope that helped!
Answer:
108.43°
Step-by-step explanation:
I graphed this expression on the graph below and found the direction angle of 108.43°.
Answer:
(x - 2)(5x + 3) = 0
Step-by-step explanation:
5x² - 7x - 6 = 0
Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 5 × - 6 = - 30 and sum = - 7
The factors are - 10 and + 3
Use these factors to split the x- term
5x² - 10x + 3x - 6 = 0 ( factor the first/second and third/fourth terms )
5x(x - 2) + 3(x - 2) = 0 ← factor out (x - 2) from each term
(x - 2)(5x - 3) = 0 ← in factored form