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maxonik [38]
3 years ago
11

A researcher is studying a mouse population in a field. For the first year of her study, she notices that the mouse population d

emonstrates exponential growth. However, by the third year of her study, the mouse population has stabilized at approximately 500 mice (although this number fluctuates a bit). Thus, 500 mice would be the _____ of the field being studied.
Mathematics
1 answer:
Montano1993 [528]3 years ago
5 0

Answer:

The 500 mice would be the carrying capacity of the field being studied.

Step-by-step explanation:

For the first year of study, the mouse population demonstrates exponential growth.

But by third year, the mouse population has stabilized at approximately 500 mice.

Thus, this 500 mice would be the carrying capacity of the field being studied.

Carrying capacity is defined as the measure to demonstrate the maximum population size that any given environment can sustain for an unspecified time period.

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There are 102102 students in a statistics class. The instructor must choose two students at random. Students in a Statistics Cla
asambeis [7]

Answer:

0.0087 probability that a freshman non-Statistics major and then a junior Statistics major are chosen at random

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

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There are 5 freshman non-Statistics majors out of 102 students.

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0.0087 probability that a freshman non-Statistics major and then a junior Statistics major are chosen at random

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3 years ago
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The percentage of cotton in material used to manufacture men's shirts follows.
velikii [3]

Answer:

Median = 34.55

Quartiles:

Q1 = 33.1

Q2 = 34.55

Q3 = 35.6

Inter Quartile range = 2.5

Step-by-step explanation:

Step 1

We arrange the given the following data from lowest to the highest

32.0, 32.1, 32.1, 32.2, 32.4, 32.5, 32.5, 32.5, 32.8, 32.8, 32.8, 32.8, 32.9, 32.9, 33.0, 33.0, 33.2, 33.2, 33.2, 33.2, 33.5, 33.6, 33.8, 33.8, 33.9, 34.0, 34.0, 34.1, 34.1, 34.3, 34.4, 34.5, 34.6, 34.6, 34.6, 34.7, 34.7, 35.0, 35.0, 35.1, 35.1, 35.2, 35.4, 35.5, 35.5, 35.5, 35.5, 35.6, 35.6, 36.1, 36.3, 36.4, 36.4, 36.4, 36.5, 36.6, 36.7, 36.7, 37.0, 37.1, 37.4, 37.4, 37.6, 37.8

a. Construct a stem-and-leaf display for the data.

Stem and leaf Display

Stem | Leaf

32 | 0,1,1,2,4,5,5,5,8,8,8,8,9,9

33 | 0,0,2,2,2,2,5,6,8,8,9

34 | 0,0,1,1,3,4,5,6,6,6,7,7

35 | 0,0,1,1,2,4,5,5,5,5,6,6,

36 | 1,3,4,4,4,5,6,7,7,

37 | 0,1,4,4,6,8

b. Calculate the median and quartiles of these data.

Number of terms = 64

1) Median = 1/2(n + 1)th value

n = 64

= 1/2(64 + 1)th

= 1/2(65)th

= 32.5 th value

This means it is between the 32nd and 33rd value

32nd = 34.5

33rd = 34.6

= 34.5 + 34.6/2

= 69.1/2

= 34.55

2) First Quartile

1/4(n + 1)th value

n = 64

= 1/4(64 + 1)th

= 1/4(65)th

= 16.5th value

This means it is between the 16th and 17th value

16th value = 33.0

17tj value = 33.2

= 33.0 + 33.2/2

= 66.2/2

= 34.55

Q1 --> 33.1

3)Second Quartile = Median

1/2(n + 1)th value

n = 64

= 1/2(64 + 1)th

= 1/2(65)th

= 32.5 th value

This means it is between the 32nd and 33rd value

32nd = 34.5

33rd = 34.6

= 34.5 + 34.6/2

= 69.1/2

= 34.55

Q2 --> 34.55

Third Quartile

3/4(n + 1)th value

n = 64

= 3/4(64 + 1)th

= 3/4(65)th

= 48.75 th value

This means it is towards the 49th value

32nd = 34.5

Hence,

Q3 --> 35.6

Inter Quartile range

Q3 - Q1

= 35.6 - 33.1

= 2.5

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3 years ago
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Likurg_2 [28]
3 probably will be the gcf of it.... or maybe 3x^3 y^3 z Not sure tho
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