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sertanlavr [38]
3 years ago
10

Anyone know the answer?

Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
5 0

Answer:

Step-by-step explanation:

Inessa05 [86]3 years ago
3 0
The answer appears to be choice 3 because it resembles an exponential function.
But I might be wrong.

Hope this helps :)


~ Your Cookie Monster
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Last month Jim drove his car 2,718.3 miles. That brought the car’s total mileage to 87,416. What was the car’s mileage before la
stich3 [128]

To solve this problem you must apply the proccedure shown below:

1. You have that Jim drove the car 2,718.3 miles for a total mileage of 87,416.

2. Then, to calculate the mileage before last month, you only need to substract the total mileage given in the exercise above and the mileage drove last month, as following:

87,416miles-2,718.3miles=84,697.7miles

Therefore, the answer is: 84,697.7 miles.

3 0
3 years ago
April shoots an arrow upward at a speed of 80 ft/sec from a platform of 25 ft. High. The pathway of the arrow can be represented
soldi70 [24.7K]

Answer:

125feet

Step-by-step explanation:

Given the equation that modeled the height expressed as h = -16t^2 + 80t + 25, where h is the height and t is the time in seconds.

The arrow reaches the maximum height at dh/dt = 0

dh/dt = -32t + 80

0= -32t+80

32t = 80

t = 80/32

t = 2.5secs

substitute t = 2.5 into the formula;

h = -16t^2 + 80t + 25

h = -16(2.5)^2 + 80(2.5) + 25

h = -16(6.25)+225

h = -100+225

h = 125

Hence the maximum height the arrow reaches is 125feet

4 0
2 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B5%7D%20%2B%5Cfrac%7B5%7D%7B7%7D%20%2B-%5Cfrac%7B1%7D%7B5%7D" id="TexFormula1"
natali 33 [55]
3/5 + 5/7 = 1 11/35 - 1/5 = 1 4/35 which is your final answer.
7 0
3 years ago
Read 2 more answers
I really don't get this. Can someone help please?
kondor19780726 [428]
Okay, so whatever the answer is to angle A its the same answer to angle C and angle B and D. the angle looks like a obtuse which means it has to be bigger than 90 degrees. use your protractor to measure it.
7 0
3 years ago
Emily drew a scale drawing of a house and its lot. The back patio is 42 millimeters long in the drawing. The actual patio is 27
kirill [66]

the scale factor used in Emily scale drawing is K = 1.63 mm/m

<h3>What scale did Emily use?</h3>

We know that Emily drew a scale drawing of a house and its lot.

In the scale drawing, the back patio is 42 millimeters long, and we know that the actual patio is 27 meters long.

Then the scale relates the measures 44mm and 27 meters, such that if the scale is K, we can write:

K*27m = 44mm

Solving for K, we can write:

K = (44/27) mm/m = 1.63 mm/m

So the scale factor used in Emily's scale drawing is K = 1.63 mm/m

If you want to learn more about scale factors:

brainly.com/question/25722260

#SPJ1

5 0
1 year ago
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