Answer:
400; 800
Explanation:
Contribution:
Product X:
= Selling price - Variable cost
= 100 - 70
= 30,
Product Y:
= Selling price - Variable cost
= 80 - 40
= 40,
Product Z:
= Selling price - Variable cost
= 25 - 20
= 5
Machine hours required :
Product X:
= Machine time per unit × Monthly demand
= 3 × 300
= 900,
Product Y:
= Machine time per unit × Monthly demand
= 2 × 200
= 400,
Product Z:
= Machine time per unit × Monthly demand
= 1 × 500
= 500
Contribution per machine hour:
Product X = Contribution ÷ Machine time per unit
= 30 ÷ 3
= 10,
Product Y = Contribution ÷ Machine time per unit
= 40 ÷ 2
= 20,
Product Z = Contribution ÷ Machine time per unit
= 5 ÷ 1
= 5
It is highest for Y, so produce maximum amount of Y, then X and then Z
Y needs 400 hrs, we are left with 800 hours, so produce 800 hours of X.
Answer:
$144,000
Explanation:
Calculation to determine net amount paid, assuming FAB wishes to minimize its cost
Net amount: ($.71 + $.01) x 200,000
Net amount = $144,000.
Therefore net amount paid, assuming FAB wishes to minimize its cost is $144000
Answer:
The future value in 5 years is $3,184.87
Explanation:
The figure is arrived by calculating the future of the yearly total service of $600($3*200) by using applicable annuity factor for each of the years from year 1 to 5.
The annuity factor for each year is calculated as (1+r)^n, where r is the rate of return of 2% and the n the year in which the service fee relates to.
Kindly find attached for detailed computations.
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