Question

How do I solve 8, 9, and 10?

Answer 1

Answer:

8)

$y-8=m(x+6)\\y-8=\frac{-4}{3}(x+6)\\\\y=\frac{-4}{3}x$

9)

$y+4.5=mx\\y=15x-4.5$

10)

$y+1=m(x-1)\\y=-2(x-1)-1\\y=-2x+1$

Step-by-step explanation:

We can use the definition of a line:

$y-y_0=m(x-x_0)$

where $y_0$ and $x_0$ co-ordinates of a point on that line, and where $m$ is the gradient of the line.

We can work out the gradient of the line by looking at the differential, or the change in y compared to the change in x.

$m=\frac{\Delta y}{\Delta x} = \frac{y_1-y_0}{x_1-x_0}$

where $(x_0,y_0)$ and $(x_1,y_1)$ are two distinct points on the line.

You now have the tools needed to go about answering these questions!