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mestny [16]
3 years ago
11

How do I solve 8, 9, and 10?

Mathematics
1 answer:
Novay_Z [31]3 years ago
4 0

Answer:

8)

y-8=m(x+6)\\y-8=\frac{-4}{3}(x+6)\\\\y=\frac{-4}{3}x

9)

y+4.5=mx\\y=15x-4.5

10)

y+1=m(x-1)\\y=-2(x-1)-1\\y=-2x+1

Step-by-step explanation:

We can use the definition of a line:

y-y_0=m(x-x_0)

where y_0 and x_0 co-ordinates of a point on that line, and where m is the gradient of the line.

We can work out the gradient of the line by looking at the differential, or the change in y compared to the change in x.

m=\frac{\Delta y}{\Delta x} = \frac{y_1-y_0}{x_1-x_0}

where (x_0,y_0) and (x_1,y_1) are two distinct points on the line.

You now have the tools needed to go about answering these questions!

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B is the midpoint of AC and E' is the midpoint of BD. If A(-9,-4), C(-1, 6), and E(-4,-3), find the coordinates of D.
Ipatiy [6.2K]
The coordinates for D are (-4, -7)

First we must locate point B as it is vital to finding the midpoint of BD. To do this, we take the average of the endpoints AC since B is its midpoint. 

x values = -9 + 1 = -8
Then divide by 2 for the average -8/2 = -4

y values = -4 + 6 = 2
Then divide by 2 for the average 2/2 = 1

Therefore B must be (-4, 1)

Now we know the values of E must be the average of B and D. So we can write equations for each coordinate since we know they are averages. 

x - values = (Bx + Dx)/2 = Ex
(-4 + Dx)/2 = -4 ---> multiply both sides by 2
-4 + Dx = -8 ---> add -4 to both sides
Dx = -4

y - values = (By + Dy)/2 = Ey
(1 + Dy)/2 = -3 ---> multiply both sides by 2
1 + Dy = -6 ---> subtract 1 from both side
Dy = -7

So the coordinates for D must be (-4, -7)
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3 years ago
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Step-by-step explanation:

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I think the answer is D but i could be wrong
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