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never [62]
2 years ago
13

Calculate the boiling point of a solution of 500.0 g of ethylene glycol (c2h6o2) dissolved in 500.0 g of water. kf = 1.86°c/m a

nd kb = 0.512°c/m. use 100°c as the boiling point of water.
Chemistry
1 answer:
Bingel [31]2 years ago
7 0

Answer:The boiling point of the solution is 108° C.

Explanation:

Boiling point of pure water=T=100^oC

Boiling point of water after addition of 500 g of ethylene glycol=T_f

Mass of water = 500g = 0.5 kg (1000 g = 1 kg)

\Delta T_f=K_b\times \frac{\text{Mass of ethlyene glycol}}{\text{Molar mass of ethylene glycol}}

\Delta T_f=0.512^oC/m\times \frac{500 g}{62.07 g/mol\times 0.5 kg}

\Delta T_f=8.24 ^oC

\Delta T_f=T_f-T

8.24^oC=T_f-100^oC

T_f=108.24^oC

The boiling point of the solution is 108° C.

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A chef plans to mix 100% vinegar with italian dressing. the italian dressing contains 13% vinegar. the chef wants to make 150 mi
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Assuming they have the same densities, then we can write this equation in terms of volume.

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Angelina_Jolie [31]

Answer:

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Explanation:

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The picture attached shows the structures, they are labeled as 1, 2 and 3, according to this problem.

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Hope this helps

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