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Len [333]
1 year ago
11

A 435.0 g sample of CaCO3 that is 95% pure gives 225L of CO2 when reacted with excess of hydrochloric acid. What is the density

in g/L of the CO2 given the reaction equation below? CaCO3(s)+2HCl(I)-CaCl2(s)+CO2(g)+H2O(I)
Chemistry
2 answers:
yulyashka [42]1 year ago
8 0

Answer:

Density = 0.85 gm/L

Explanation:

Check the attached image for solution.

horsena [70]1 year ago
3 0
Density = 0.82 gm/L


Explanation:
Caco3= 40+12+16x2
= 100gm

CO2= 12+16x2
=44 gm

44/100 x 435

= 191.4gm


The mass of CO2 = 191.4gm
Volume of co2= 225L


Density= mass/volume = 191.4gm/225 L


= 0.85 gm/L
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The ratio of x to y is 4 to 12. Fill in numbers to<br>form a table with the given ratio,​
murzikaleks [220]

Answer:

Explanation:

x                                     y

4                                     12

8                                     24

12                                   36

16                                   48

20                                  60

           

4 0
3 years ago
Iron is extracted from iron oxide in the Blast Furnace: Fe 2 O 3 + 3 CO → 2 Fe + 3 CO 2
arsen [322]

a. mass of iron = 69.92 g

b. percent yield = 93%

<h3>Further eplanation </h3>

Percent yield is the compare of the amount of product obtained from a reaction with the amount you calculated

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

An actual yield is the amount of product actually produced by the reaction. A theoretical yield is the amount of product that you calculate from the reaction equation according to the product and reactant coefficients

a.

Reaction

Fe₂O₃+3CO⇒2Fe+3CO₂

MW Fe₂O₃ :  159.69 g/mol

mol Fe₂O₃

\tt \dfrac{100}{159,69}=0.626

mol Fe₂O₃ : mol Fe = 1 : 2

mol Fe :

\tt \dfrac{2}{1}\times 0.626=1.252

mass of Fe(Ar=55.845 g/mol) :

\tt 1.252\times 55.845=69.92~g

b.

actual yield = 65 g

theoretical yield = 69.92 g

percent yield :

\tt =\dfrac{65}{69.92}=0.93=93\%

8 0
3 years ago
Which phase is heat energy being released?
scZoUnD [109]

The answer is B
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6 0
2 years ago
What is the maximum amount of kcl that can dissolve in 200 g of water? (the solubility of kcl is 34 g/100 g h2o at 20°c.)?
Svetllana [295]
The correct answer is 68 g
hope this helps!!
8 0
3 years ago
Read 2 more answers
Given the equation C3H8(g) + O2(g) = CO2(g) + H2O(g) and that the enthalpies of formation for H2O(g) = -241.8 kJ/mol, CO2(g) = -
kari74 [83]

Answer: 72.4 kJ/mol

Explanation:

The balanced chemical reaction is,

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(l)  \Delta H=-2220.1kJ/mol

The expression for enthalpy change is,

\Delta H=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

\Delta H=[(n_{CO_2}\times \Delta H_{CO_2})+(n_{H_2O}\times \Delta H_{H_2O})]-[(n_{O_2}\times \Delta H_{O_2})+(n_{C_3H_8}\times \Delta H_{C_3H_8})]

where,

n = number of moles

\Delta H_{O_2}=0 (as heat of formation of substances in their standard state is zero

Now put all the given values in this expression, we get

-2220.1=[(3\times -393.5)+(4\times -241.8)]-[(5\times 0)+(1\times \Delta H_{C_3H_8})]

\Delta H_{C_3H_8}=72.4kJ/mol

Therefore, the heat of formation of propane is 72.4 kJ/mol

7 0
2 years ago
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