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Len [333]
1 year ago
11

A 435.0 g sample of CaCO3 that is 95% pure gives 225L of CO2 when reacted with excess of hydrochloric acid. What is the density

in g/L of the CO2 given the reaction equation below? CaCO3(s)+2HCl(I)-CaCl2(s)+CO2(g)+H2O(I)
Chemistry
2 answers:
yulyashka [42]1 year ago
8 0

Answer:

Density = 0.85 gm/L

Explanation:

Check the attached image for solution.

horsena [70]1 year ago
3 0
Density = 0.82 gm/L


Explanation:
Caco3= 40+12+16x2
= 100gm

CO2= 12+16x2
=44 gm

44/100 x 435

= 191.4gm


The mass of CO2 = 191.4gm
Volume of co2= 225L


Density= mass/volume = 191.4gm/225 L


= 0.85 gm/L
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lora16 [44]

The equation that is a decomposition reaction is

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That is option D.

<h3>Properties of a decomposition reaction</h3>

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A hypothetical element has three main isotopes with mass numbers of 51, 53, and 54. If 15.00% of the isotopes have a mass number
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3 years ago
A mixture of 0.10 mol of NO, 0.050 mol of H2, and 0.10 mol of H2O is placed in a 1.0-L vessel at 300 K. The following equilibriu
tatyana61 [14]

Answer:

[H2] =    0.012 M

[N2] =    0.019 M

[H2O] =  0.057 M

Explanation:

The strategy here is to account for the species at equilibrium given that the concentration of [NO]=0.062M at equilibrium is known and the quantities initially present and its stoichiometry.

                  2NO(g)         +    2H2(g)    ⇒        N2(g)      +         2H2O(g)

i  mol            0.10                   0.050                                             0.10

c mol            -0.038                -0.038                +0019                +0.038                                                

e mol            0.062                 0.012                  00.019               0.057

Since the volume of the vessel is 1.0 L, the concentrations in molarity are:

[NO] =   0.062 M

[H2] =    0.012 M

[N2] =    0.019 M

[H2O] =  0.057 M

5 0
2 years ago
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