A 435.0 g sample of CaCO3 that is 95% pure gives 225L of CO2 when reacted with excess of hydrochloric acid. What is the density

Question

Len [333]

2 years ago

11

A 435.0 g sample of CaCO3 that is 95% pure gives 225L of CO2 when reacted with excess of hydrochloric acid. What is the density

in g/L of the CO2 given the reaction equation below? CaCO3(s)+2HCl(I)-CaCl2(s)+CO2(g)+H2O(I)

Chemistry

2 answers:

yulyashka [42] · Answer 1 · 2023-11-20T21:10:36+03:00

yulyashka [42]2 years ago

8 0

Answer:

Density = 0.85 gm/L

Explanation:

Check the attached image for solution.

horsena [70] · Answer 2 · 2023-11-20T23:30:51+03:00

horsena [70]2 years ago

3 0

Density = 0.82 gm/L

Explanation:
Caco3= 40+12+16x2
= 100gm

CO2= 12+16x2
=44 gm

44/100 x 435

= 191.4gm

The mass of CO2 = 191.4gm
Volume of co2= 225L

Density= mass/volume = 191.4gm/225 L

= 0.85 gm/L