Pattern A starts with 20 and substracts 3
First number = 20
Second number = 20 - 3 = 17
Third number = 17 - 3 = 14
Fourth number = 14 - 3 = 11
Pattern B starts with 10 and adds 2
First number = 10
Second number = 10 + 2 = 12
Third number = 12 + 2 = 14
Fourth number = 14 + 2 = 16
Now join pattern A and B
First combination = (20,10)
Second combination = (17,12)
Third combination = (14, 14)
Fourth combination = (11, 16)
The answer is d. (20,10), (17,12), (14,14), (11,16)
Answer:
using pythagoras theorem
H^2=P^2+B^2
here h=MN ,opposite(P) be 15 and adjacent(B) be 16
(MN)2=15^2+16^2
(MN)^2=225+256
MN=
MN=21.93
after rounding off MN=21.9
Step-by-step explanation:
40(60/100) 4(6/10) =24/10 = 2.4
