An hemispherical dome is half a sphere. If the diameter is 60 m, then the radius is 30 m.
We can use differentials to solve this problem because we are adding a thin layer to the original dome, so the volume of the dome in increased by a differential of itself.
This differential volume that the dome is increased is equal to the volume of the coat of paint.
The volume of the dome can be written as:

Now, we can calculate dV as:

Answer: the paint needed for this coat is approximately 7.92 m^3
To get 10 % you have to divide by 10 .
so 154.99 ÷ 10 = 15.499.
that's 10% but you want 20% so you times 10% by 2.
15.499 X 2 = 30.998.
154.99 - 30.998 = 123.992.
you then need to round the answer so you get $123.99
Hope this helps!!
Answer:
58 %
Step-by-step explanation:
So 18 % of the beads are green and 40 are purple add those and you get 58
Answer:
(-2, 20)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Coordinates (x, y)
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = -7x + 6
y = -10x
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em> [1st Equation]: -10x = -7x + 6
- [Addition Property of Equality] Add 7x on both sides: -3x = 6
- [Division Property of Equality] Divide -3 on both sides: x = -2
<u>Step 3: Solve for </u><em><u>y</u></em>
- Substitute in <em>x </em>[2nd Equation]: y = -10(-2)
- Multiply: y = 20
The total amount of money accrued ( principal and interest ) in 35 years is $570.78.
<h3>What is the total amount accrued?</h3>
The formula for compound interest is expressed as;
A = P( 1 + r/t )^(n×t)
Given the data in the question;
- Principal P = $200
- Rate r = 3% = 3/100 = 0.03
- Compounded monthly n = 12
- Time t = 35
- Amount accrued in 35 years A = ?
Plug the given values into the equation above.
A = P( 1 + r/n )^(n×t)
A = 200( 1 + 0.03/12 )^(12×35)
A = 200( 1 + 0.0025 )^(420)
A = 200( 1.0025 )^(420)
A = 200( 2.85390914 )
A = $570.78
Therefore, the total amount of money accrued ( principal and interest ) in 35 years is $570.78.
Learn more about compound interest here: brainly.com/question/27128740
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