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3 years ago

Find the surface area of the prism

Mathematics

1 answer:

Anastasy [175]3 years ago

4 0

slated surface

17 × 20 = 340

2 triangle sides

2 × 8 × 15 ÷ 2 = 120

backside

8 × 20 = 160

bottom

15 × 20 = 300

sum all of it

340 + 120 + 160 + 300 = 920

can I get brainliest

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What is Factor tree of 495?

Masteriza [31]

Prime Factors of 495 =3, 3, 5, 11

Which is the same as = 32 x 5 x 11Prime Factors Tree of 495495
/ \
3 165/ \
3 55/ \
5 11/ \
11 1

7 0

3 years ago

Read 2 more answers

Find the indefinite integral using the substitution x = 10 sin(θ). (Use C for the constant of integration.) 1 (100 − x2)3/2 dx

soldi70 [24.7K]

Answer:

The indefinite integral

= $\frac{1}{100}$ ˣ $\frac{x}{\sqrt{100-x^{2} } }$ ⁺ C

Step-by-step explanation:

x= 10sinθ

dx = 10cosθdθ

the step-to-step explanation is in the attachment

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3 years ago

Lan silmeyin sicarim ağzınıza amk

erma4kov [3.2K]

Answer:

sikdirin gidin götü boklular

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3 years ago

⦁ In a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football. Construct a 95% confiden

fomenos

Answer:

95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

Step-by-step explanation:

We are given that in a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football.

Firstly, the pivotal quantity for 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = proportion of adults in the United States whose favorite sport to watch is football in a sample of 1219 adults = $\frac{354}{1219}$

n = sample of US adults = 1291

p = population proportion of adults

Here for constructing 95% confidence interval we have used One-sample z proportion statistics.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

significance level are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ]

= [ $\frac{354}{1219}-1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} }$ , $\frac{354}{1219}+1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} }$ ]

= [0.265 , 0.316]

Therefore, 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

5 0

3 years ago

Help please!! 7&8 I don’t understand

Andrej [43]

Answer:

7. 4

8. -2

Step-by-step explanation:

domain gose right so it should be 4 range goes down so it should be -2

7 0

3 years ago